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GarryVolchara [31]
3 years ago
5

What is the product? (X4)(3x3-2)(4x2 +5x)

Mathematics
2 answers:
matrenka [14]3 years ago
8 0

Answer:

12x⁹ + 15x⁸ - 8x⁶ - 10x⁵

Step-by-step explanation:

<u>Solution with steps, expand to get the polynomial:</u>

  • x⁴ • (3x³ - 2) • (4x² + 5x) =
  • x⁵• (3x³ - 2) • (4x + 5) =
  • x⁵• (12x⁴ + 15x³  - 8x - 10) =
  • 12x⁹ + 15x⁸ - 8x⁶ - 10x⁵
liraira [26]3 years ago
6 0
X5 • (3x3 - 2) • (4x + 5)

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A quadratic equation has zero real number solutions. Which could be the discriminant value associated with this equation?
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MCR3U1 Culminating 2021.pdf
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Answer:

(a) y = 350,000 \times (1 + 0.07132)^t

(b) (i) The population after 8 hours is 607,325

(ii) The population after 24 hours is 1,828,643

(c) The rate of increase of the population as a percentage per hour is 7.132%

(d) The doubling time of the population is approximately, 10.06 hours

Step-by-step explanation:

(a) The initial population of the bacteria, y₁ = a = 350,000

The time the colony grows, t = 12 hours

The final population of bacteria in the colony, y₂ = 800,000

The exponential growth model, can be written as follows;

y = a \cdot (1 + r)^t

Plugging in the values, we get;

800,000 = 350,000 \times (1 + r)^{12}

Therefore;

(1 + r)¹² = 800,000/350,000 = 16/7

12·㏑(1 + r) = ㏑(16/7)

㏑(1 + r) = (㏑(16/7))/12

r = e^((㏑(16/7))/12) - 1 ≈ 0.07132

The  model is therefore;

y = 350,000 \times (1 + 0.07132)^t

(b) (i) The population after 8 hours is given as follows;

y = 350,000 × (1 + 0.07132)⁸ ≈ 607,325.82

By rounding down, we have;

The population after 8 hours, y = 607,325

(ii) The population after 24 hours is given as follows;

y = 350,000 × (1 + 0.07132)²⁴ ≈ 1,828,643.92571

By rounding down, we have;

The population after 24 hours, y = 1,828,643

(c) The rate of increase of the population as a percentage per hour =  r × 100

∴   The rate of increase of the population as a percentage = 0.07132 × 100 = 7.132%

(d) The doubling time of the population is the time it takes the population to double, which is given as follows;

Initial population = y

Final population = 2·y

The doubling time of the population is therefore;

2 \cdot y = y \times (1 + 0.07132)^t

Therefore, we have;

2·y/y =2 = (1 + 0.07132)^t

t = ln2/(ln(1 + 0.07132)) ≈ 10.06

The doubling time of the population is approximately, 10.06 hours.

8 0
3 years ago
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