Answer:
yea dude thats a whole project you cant just put it on brainly and expect us to do it for you. stop being lazy and abusing the website
Step-by-step explanation:
3 + (2 + 8)^2 / 4 * (1/2)^4
3 + 10^2 / 4 * (1/2)^4
3 + 100/4 * (1/2)^4
3 + 25 * 1/16
3 + 25/16
48/16 + 25/16
73/16
4 9/16 <==
The data are skewed and there is an outlier statement first is correct.
<h3>What is the box and whisker plot?</h3>
A box and whisker plot is a method of abstracting a set of data that is approximated using an interval scale. It's also known as a box plot. These are primarily used to interpret data.
We have data on the box plot.
Because the dots decrease as the number line grows, the depicted dot plot is skewed right.
The graph's "tail" is pushed toward greater positive numbers. As a result, the mean is pushed towards the graph's tail and is higher than the median.
Thus, the data are skewed and there is an outlier statement first is correct.
Learn more about the box and whisker plot here:
brainly.com/question/3209282
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M can be any positive real number.
Explanation:
From f(x) = √(mx) ; if x is posive m has to be positive; if x is negative m has to be negative; if x is cero m can have any value, and the range will always be 0 or positve
From g(x) = m √x; x can only be 0 or positive and the range will have the sign of m.
Given we concluded that the range of f(x) can only be 0 or positive, then me can only be 0 or positive.
Answer:
Systolic on right
Systolic on left
So for this case we have more variation for the data of systolic on left compared to the data systolic on right but the difference is not big since 0.170-0.147 = 0.023.
Step-by-step explanation:
Assuming the following data:
Systolic (#'s on right) Diastolic (#'s on left)
117; 80
126; 77
158; 76
96; 51
157; 90
122; 89
116; 60
134; 64
127; 72
122; 83
The coefficient of variation is defined as " a statistical measure of the dispersion of data points in a data series around the mean" and is defined as:
And the best estimator is 
Systolic on right
We can calculate the mean and deviation with the following formulas:
[te]\bar x = \frac{\sum_{i=1}^n X_i}{n}[/tex]
For this case we have the following values:
So then the coeffcient of variation is given by:
Systolic on left
For this case we have the following values:
So then the coeffcient of variation is given by:
So for this case we have more variation for the data of systolic on left compared to the data systolic on right but the difference is not big since 0.170-0.147 = 0.023.
