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Nikolay [14]
3 years ago
9

Liam has a free throw percentage of 0.64. If he takes 6 free throw shots in a game, what is the probability that he will make al

l 6?
Mathematics
2 answers:
Flauer [41]3 years ago
8 0
He will make 0.64 at each if you wanna ant the total multiply 0.64 by 6 and that will be your answer
siniylev [52]3 years ago
4 0

Answer:

0.687

Step-by-step explanation:

I did it on USATESTPREP and that is the correct answer

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Percy delivers pizzas for pizza king. He is paid $6 an hour plus $2.50 for each pizza he delivers. Percy earned $280 last week.
Triss [41]
Hey You!

6 × 30 = 90

280 - 90 = 190

190 / 2.50 = 76

We can check using multiplication.

2.50 × 76 = 190

Percy delivered 76 pizzas.
7 0
3 years ago
What is (3 x 20) + 9 and what is (4 x 100) + 20?
madreJ [45]

Answer:

(3 x 20) + 9 = 69

4 x 100) + 20 = 420

7 0
3 years ago
Read 2 more answers
F(x) = x2 − x − ln(x) (a) find the interval on which f is increasing. (enter your answer using interval notation.) find the inte
Mekhanik [1.2K]

Answer:

(a) Decreasing on (0, 1) and increasing on (1, ∞)

(b) Local minimum at (1, 0)

(c) No inflection point; concave up on (0, ∞)

Step-by-step explanation:

ƒ(x) = x² - x – lnx

(a) Intervals in which ƒ(x) is increasing and decreasing.

Step 1. Find the zeros of the first derivative of the function

ƒ'(x) = 2x – 1 - 1/x = 0

           2x² - x  -1 = 0

     ( x - 1) (2x + 1) = 0

         x = 1 or x = -½

We reject the negative root, because the argument of lnx cannot be negative.

There is one zero at (1, 0). This is your critical point.

Step 2. Apply the first derivative test.

Test all intervals to the left and to the right of the critical value to determine if the derivative is positive or negative.

(1) x = ½

ƒ'(½) = 2(½) - 1 - 1/(½) = 1 - 1 - 2 = -1

ƒ'(x) < 0 so the function is decreasing on (0, 1).

(2) x = 2

ƒ'(0) = 2(2) -1 – 1/2 = 4 - 1 – ½  = ⁵/₂

ƒ'(x) > 0 so the function is increasing on (1, ∞).

(b) Local extremum

ƒ(x) is decreasing when x < 1 and increasing when x >1.

Thus, (1, 0) is a local minimum, and ƒ(x) = 0 when x = 1.

(c) Inflection point

(1) Set the second derivative equal to zero

ƒ''(x) = 2 + 2/x² = 0

             x² + 2 = 0

                   x² = -2

There is no inflection point.

(2). Concavity

Apply the second derivative test on either side of the extremum.

\begin{array}{lccc}\text{Test} & x < 1 & x = 1 & x > 1\\\text{Sign of f''} & + & 0 & +\\\text{Concavity} & \text{up} & &\text{up}\\\end{array}

The function is concave up on (0, ∞).

6 0
3 years ago
7 1/4 % as a decimal
Mila [183]
7 1/4% equals 7.25% and there is your answer.
8 0
3 years ago
What is the equation of the circle with center (-3,1) that passes through the point (-5, 3)?
Natali5045456 [20]

Answer:

Option B) (x + 3)^2 + (y – 1)^2 = 8 is the correct answer.

Step-by-step explanation:

The equation of a circle with center (h,k) and radius r is given by:

(x-h)^2 + (y-k)^2 = r^2

Given

Center = (h,k) = (-3,1)

=> h = -3

=> k = 1

The distance between the center of circle and the point through which the circle passes will be the radius.

The distance formula is given by:

r = \sqrt{(x_2-x_1)^2+(y_2-y_1)^2

Given

(x_1,y_1) = (-3,1)\\(x_2,y_2) = (-5,3)

Putting the values in the formula

r = \sqrt{(-5+3)^2+(3-1)^2}\\r = \sqrt{(-2)^2+(2)^2}\\r = \sqrt{4+4}\\r = \sqrt{8}

Putting the values of h,k and r in general form of equation

\{x-(-3)}^2\} +(y-1)^2 = (\sqrt{8})^2\\(x+3)^2+(y-1)^2 = 8

Hence,

Option B) (x + 3)^2 + (y – 1)^2 = 8 is the correct answer.

4 0
3 years ago
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