Answer:
See below for an explanation
Step-by-step explanation:
I'm unsure of your answer choices, so I'll show you how to solve for the remainder of the whole triangle:
Since we are given a hypotenuse of 5 and a side length of 4 which is adjacent to ∅, the trig function to solve for ∅ would be cosine because cos∅=adjacent/hypotenuse (SOHCAHTOA). This means cos∅=4/5 and taking the arccos (the inverse of cosine aka. cos^-1) of both sides gets us ∅=36.87°
Side AC can be solved by using the Pythagorean Theorem since a²+b²=c² can be turned into 4²+b²=5². We would then have 16+b²=25 which is also b²=9, thus taking the square root of both sides gives us b=3 (since distance is positive). Thus, side AC has a length of 3 units.
∠A can be found by using the Triangle Angle-Sum Theorem. Since all the interior angles of a triangle must add up to 180°, then ∠A+∠B+∠C=180°. We know that since ∠B=36.87° and ∠C=90°, then we have the equation ∠A+36.87°+90°=180°. Combining like terms on the left side gets us ∠A+126.87°=180° and subtracting on both sides get us ∠A=53.13°
<u>Final sides and angles of the triangle:</u>
∠A=53.13°
∠B=36.87°
∠C=90°
BC=4
BA=5
AC=3
Answer: I believe it is 2/3
Step-by-step explanation: count from point -4,-4 over 2 (to the right) up 3
Answer:
b
Step-by-step explanation:
I went through and tested each of the answers and it is b.
Answer:
oh ok. So, first, you get the equation in the form y=ax2+bx+c. Next, you calculate -b / 2a. This is the x-coordinate of the vertex. Then finally, you plug in the value of -b / 2a into the equation into the x variable and solve for the y variable. This is the coordinate of the vertex.
Step-by-step explanation:
Hope this helps!
Answer:
-sqrt(5) ≤ x ≤ sqrt(5)
Step-by-step explanation:
x^2-5≤0
Add 5 to each side
x^2-5+5≤0+5
x^2 ≤5
Take the square root of each side, remembering to flip the inequality for the negative sign. Since this is less than we use and in between
sqrt(x^2) ≤ sqrt(5) and sqrt(x^2) ≥ -sqrt(5)
x ≤ sqrt(5) and x ≥- sqrt(5)
-sqrt(5) ≤ x ≤ sqrt(5)