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Natalka [10]
3 years ago
10

How do I find the lengths of A and B?

Mathematics
2 answers:
bija089 [108]3 years ago
8 0
Sin(53)=a/6 
a=6*sin(53)=4.7918

Cos(53)=b/6
b=6*cos(37)=3.6109
11111nata11111 [884]3 years ago
4 0
All you have to do it <span>Identify the legs and the hypotenuse of the triangle. You know that the triangle is a right triangle since the ground and the raised portion of the porch are perpendicular—this means you can use the Pythagorean Theorem to solve this problem. Identify a, </span>b<span>, and c. Use the Pythagorean Theorem to find the </span>length<span> of c.</span>
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I NEED HELP ASAPPPPPPPPPPP
tangare [24]

Answer:

C. f(x) = x + 1

Step-by-step explanation:

0 = -1 + 1

1 = 0 + 1

2 = 1 + 1

3 = 2 + 1

f(x) = x + 1

7 0
3 years ago
Read 2 more answers
Madumita is asked by her cousin to deliver a box containing 20 chocolates to her friend. Madumita is promised a reward of 10₨ fo
pogonyaev

Answer:

75Rs

Step-by-step explanation:

This can be solved by turning the information in the prompt into two equations, 20 = E + D, and (10 x D) - (15 x E) = M. For this, E represents the number of chocolates Madumita ate along the way, D represents the number of chocolates she successfully delivered, and M represents how much money she will receive from her cousin: what we are looking for. Since they give us the number she ate along the way (E), we can plug that in to the first equation to find D.  ( 20 = 5 + D  ---->  15 = D ) Now that we have E and D, we can plug them into the second equation to find M.   (10 x 15) - (15 x 5) = M  -----> 150 - 75 = 75Rs.

6 0
3 years ago
Need help with this problem
Ber [7]

\frac{2x}{x + 3}  - \frac{3}{x - 4}

The LCM of x+3 and x-4 is x² - x - 12

Working out gives;

\frac{2x^2 - 8x - 3x - 9}{x^2 - x - 12}  = \frac{2x^2 - 11x - 9}{x^2 - x - 12}

Simplify further using equations calculator to get the answer as attached below:

4 0
3 years ago
What is the distributive property of 6(5-9)
IgorC [24]

The distributive property of multiplication is a very useful property that lets you simplify expressions in which you are multiplying a number by a sum or difference. The property states that the product of a
5 0
3 years ago
Please help I’ll give brainliest
damaskus [11]
The piecewise function all the way to the left (x + 3) should have an ending point shaded in. [At x = -2] The next function ((x^2) -1) should have both ending points left unshaded. Finally, the logarithm function should have a shaded in starting point [At x = 1] and should have an unshaded ending point at x = 3.
6 0
3 years ago
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