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2 years ago

This is due tomorrow and PLEASE HELP ME ON THESE QUESTIONS! THIS IS DUE TOMORROW!

Mathematics

1 answer:

Usimov [2.4K]2 years ago

4 0

3: multiply the change per minute by how many minutes: 3.1x15=46.5. 5: Is your opinion, I can't tell you how to feel. But a negative times a negative is a positive, so if there is an even number of negatives no matter how many positives there are it will be positive, if there is an odd number of negatives it will be negative. :) Hope this helps!

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F(x)=x2 what is g(x)?

Oksi-84 [34.3K]

g(x) = (1/4)x^2 . correct option C) .

<u>Step-by-step explanation:</u>

Here we have , $f(x)=x^2$ and we need to find g(x) from the graph . Let's find out:

We have , $f(x)=x^2$ . From the graph we can see that g(x) is passing through point (2,1 ) . Let's substitute this point in all of the four options !

A . g(x) = (1/4x)^2

Putting (2,1) in equation g(x) = (x/4)^2 , we get :

⇒ $g(2)= (\frac{2}{4} )^2$

⇒ $1\neq \frac{1}{4}$

Hence , wrong equation !

B . g(x) = 4x^2

Putting (2,1) in equation g(x) = 4x^2 , we get :

⇒ $g(2)=4(2)^2$

⇒ $1\neq 64$

Hence , wrong equation !

C . g(x) = (1/4)x^2

Putting (2,1) in equation g(x) = (1/4)x^2 , we get :

⇒ $g(2)= (\frac{1}{4} )2^2$

⇒ $1= 1$

Hence , right equation !

D . g(x) = (1/2)x^2

Putting (2,1) in equation g(x) = (1/2)x^2 , we get :

⇒ $g(2)= (\frac{1}{2} )2^2$

⇒ $1\neq 2$

Hence , wrong equation !

Therefore , g(x) = (1/4)x^2 . correct option C) .

8 0

3 years ago

Four times the sum of 8 and some number is 4. What is the number?

Lunna [17]

Answer:

$\Huge \boxed{\mathrm{-7}}$

$\rule[225]{225}{2}$

Step-by-step explanation:

Let the number be x.

$4(x+8)=4$

Dividing both sides by 4,

$x+8=1$

Subtracting 8 from both sides,

$x=-7$

The number is -7.

$\rule[225]{225}{2}$

3 0

3 years ago

Read 2 more answers

What is 104.35 x 34?

Luden [163]

Answer:

3547.90

Step-by-step explanation:

3 0

2 years ago

Answer this maths question.

zvonat [6]

Answer:

IM NOT ABLE SEE THE QUESTION

Step-by-step explanation:

PLEASE TYPE AND SEND IT

8 0

3 years ago

Read 2 more answers

Solving Rational equations. LCD method. Show work. Image attached.

posledela

$(k-2)(k-6)=k^2-2k-6k+12=k^2-8k+12$

So in order to get all the fractions to have a common denominator, we need to multiply $\dfrac k{k-2}$ by $\dfrac{k-6}{k-6}$ , and $\dfrac1{k-6}$ by $\dfrac{k-2}{k-2}$ :