I was thinking that the answer could be
2.810; log3 21.903
OR
<span> 2.810; log3 55.2 </span>
So,<span> log5 of 92 is between 2.5 and 3 Correct answer is A</span>
we know that
If a ordered pair (x,y) is a solution of the equation, then the ordered pair must satisfy the equation
we have the equation
![7x-5y=28](https://tex.z-dn.net/?f=7x-5y%3D28)
Let's verify all the cases to determine the solution to the problem.
<u>case A)</u> point ![(-6,-14)](https://tex.z-dn.net/?f=%28-6%2C-14%29)
Substitute the values of x and y in the equation
![x=-6\\y=-14](https://tex.z-dn.net/?f=x%3D-6%5C%5Cy%3D-14)
![7(-6)-5(-14)=28](https://tex.z-dn.net/?f=7%28-6%29-5%28-14%29%3D28)
![-42+70=28](https://tex.z-dn.net/?f=-42%2B70%3D28)
-------> is true
therefore
The point
is a solution of the equation
<u>case B)</u> point ![(-1,-7)](https://tex.z-dn.net/?f=%28-1%2C-7%29)
Substitute the values of x and y in the equation
![x=-1\\y=-7](https://tex.z-dn.net/?f=x%3D-1%5C%5Cy%3D-7)
![7(-1)-5(-7)=28](https://tex.z-dn.net/?f=7%28-1%29-5%28-7%29%3D28)
![-7+35=28](https://tex.z-dn.net/?f=-7%2B35%3D28)
-------> is true
therefore
The point
is a solution of the equation
<u>case C)</u> point ![(4,10)](https://tex.z-dn.net/?f=%284%2C10%29)
Substitute the values of x and y in the equation
![x=4\\y=10](https://tex.z-dn.net/?f=x%3D4%5C%5Cy%3D10)
![7(4)-5(10)=28](https://tex.z-dn.net/?f=7%284%29-5%2810%29%3D28)
![28-50=28](https://tex.z-dn.net/?f=28-50%3D28)
-------> is not true
therefore
The point
is not a solution of the equation
<u>case D)</u> point ![(7,9)](https://tex.z-dn.net/?f=%287%2C9%29)
Substitute the values of x and y in the equation
![x=7\\y=9](https://tex.z-dn.net/?f=x%3D7%5C%5Cy%3D9)
![7(7)-5(9)=28](https://tex.z-dn.net/?f=7%287%29-5%289%29%3D28)
![49-45=28](https://tex.z-dn.net/?f=49-45%3D28)
-------> is not true
therefore
The point
is not a solution of the equation
therefore
<u>the answer is </u>
![(-6,-14)](https://tex.z-dn.net/?f=%28-6%2C-14%29)
![(-1,-7)](https://tex.z-dn.net/?f=%28-1%2C-7%29)
Answer:
sorry this question is tough
Off topic, I like your username :] good luck with whomever answers though <33