If A=(3,2) and B=(5,7) be two points , find the unit vector along BA
1 answer:
If we were to plot the points on a graph, we could draw a straight lint between them. The question wants us to find the length of this line. We could make a right triangle with this line as the hypotenuse, with an x length of 2(y2-y1) and a y length of 5 (y2-y1). From there we can find the hypotenuse with Pythagorean Theorem: c^2=a^2+b^2.
c^2=(2)^2+(5)^2
c^2=4+25
C^2=41
c=
Decimal approximation: 6.403
Hope this helps!
c^2=(2)^2+(5)^2
c^2=4+25
C^2=41
c=
Decimal approximation: 6.403
Hope this helps!
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The graph of a quadratic function passes through the points (5,31) (3,11) (0,11).
To find:
The equation of the quadratic function.
Solution:
A quadratic function is defined as:
...(i)
It is passes through the point (0,11). So, substitute in (i).
Putting in (i), we get
...(ii)
The quadratic function passes through the point (5,31). So, substitute in (ii).
Divide both sides by 5.
...(iii)
The quadratic function passes through the point (3,11). So, substitute in (ii).
Divide both sides by 3.
...(iv)
Subtracting (iv) from (iii), we get
Putting in (iv), we get
Putting in (ii), we get
Therefore, the required quadratic equation is .