If we were to plot the points on a graph, we could draw a straight lint between them. The question wants us to find the length of this line. We could make a right triangle with this line as the hypotenuse, with an x length of 2(y2-y1) and a y length of 5 (y2-y1). From there we can find the hypotenuse with Pythagorean Theorem: c^2=a^2+b^2. c^2=(2)^2+(5)^2 c^2=4+25 C^2=41 c= Decimal approximation: 6.403