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3 years ago

Which is larger 1:40 or 1:60

Mathematics

1 answer:

agasfer [191]3 years ago

3 0

1:40.

1:40 is equal to 1/40, while 1:60 is equal to 1/60.

1/40 is the bigger fraction, so 1:40 is the correct answer.

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Use the elimination method to solve the system of equations. Choose the correct ordered pair<br>

UkoKoshka [18]

Answer:

Answer is B

Step-by-step explanation:

$12x - y = 25 \\ 9x + y = 17 \\ x = \frac{17 - y}{9} \\ 12( \frac{17 - y}{9} ) - y = 25 \\$

$\frac{204}{9} - \frac{12}{9} y - y = 25 \\ \frac{204}{9} - \frac{21y}{9} = 25 \\ - \frac{21y}{9} = 25 - \frac{204}{9} \\ - \frac{21y}{9} = 2.33 \\ - 21y = 20.997 \\ y = - 0.99$

$y = - 1 \\ x = \frac{17 - y}{9} \\ x = \frac{17 - - 1}{9} = \frac{18}{9} \\ x = 2$

5 0

3 years ago

Last year, Nicholas started babysitting to earn extra spending money. Over the summer, he tracked how much money he earned at ea

Ierofanga [76]

Answer:

25%

Step-by-step explanation:

The 5 values of the given box plot are;

The minimum value = 20

The first quartile, the 25th percentile point, Q₁ = 25

The median or second quartile, the 50th percentile point, Q₂ = 30

The third quartile, the 75th percentile point, Q₃ = 40

The maximum value = 55

The range = The maximum value - The minimum value

∴ The range = 55 - 20 = 35

We note that Nicholas earned $25 or less from the minimum value up to first quartile, Q₁, which is the 25th percentile point, where we have 25 percent of the data points

Therefore, the percent of the time Nicholas earned $25 or less is 25 percent of the time.

8 0

2 years ago

A combined total of $46,000 is invested in two bonds that pay 4% and

valkas [14]

Answer: 4%-16000 and 9.5%-30000

Why:

1) x+y=46000

x=46000-y

2) 4%x+9,5%y=3490;

4x + 9.5y=349000; so 4*(46000-y)+9.5y=349000;

5.5y=165000

y=30000

x=46000-30000=16000

5 0

3 years ago

192/38 with remanders

guapka [62]

Answer:

5 Remainder 2

3 0

2 years ago

Read 2 more answers

Explain why if a runner completes a 6.2â-mi race in 32 âmin, then he must have been running at exactly 11 âmi/hr at least twice

MA_775_DIABLO [31]

Answer:

Accelerating to top speed, deaccelerating to finish line.

Step-by-step explanation:

If the runner kept a constant speed of 11 mph for the whole duration of his run (32 minutes), the distance he would have covered is:

$d=11*\frac{32}{60}\\d= 5.87\ mi$

This means that, in order to run the full 6.2 miles, the runner needs to reach a speed over 11 mph. Assume he starts from rest, while accelerating the runner reaches, and the surpasses, the 11 mph mark. Since his speed at the finish line is zero, the runner has to deaccelerate from his current running speed (which should be higher than 11 mph), passing through 11 mph and reaching zero at the finish line.

3 0

3 years ago