Your question: Find D in | - 2d|<10
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SOLVING....
Solve the absolute value
|−2d| < 10
=
−2d < 10
or
−2d > −10
Solve −2d < 10 for D
Divide each side by -2
-2d ÷ -2 < 10 ÷ -2
d > -5
Now Solve −2d > −10
Divide each side by -2
-2d ÷ -2 > -10 ÷ -2
d < 5
So D is d < 5 and d > -5
Answer:
1. 8 quarts of blue
2. 12 quarts of yellow
3. 10 pints of red
4. 24 pints of yellow
5. 16 quarts of light blue
6. 9 quarts of red
Answer:
A(t) = 300 -260e^(-t/50)
Step-by-step explanation:
The rate of change of A(t) is ...
A'(t) = 6 -6/300·A(t)
Rewriting, we have ...
A'(t) +(1/50)A(t) = 6
This has solution ...
A(t) = p + qe^-(t/50)
We need to find the values of p and q. Using the differential equation, we ahve ...
A'(t) = -q/50e^-(t/50) = 6 - (p +qe^-(t/50))/50
0 = 6 -p/50
p = 300
From the initial condition, ...
A(0) = 300 +q = 40
q = -260
So, the complete solution is ...
A(t) = 300 -260e^(-t/50)
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The salt in the tank increases in exponentially decaying fashion from 40 grams to 300 grams with a time constant of 50 minutes.
Answer:
Arranging from longest (at top) to shortest (at bottom)
DF
EF
DE
Step-by-step explanation:
We need to place the sides of triangle DE, DF and EF from longest to shortest.
The triangle has longest side that is opposite to the largest angle
We know two angles < E= 61° , <F= 59° we need to find <D
Sum of angles of triangle = 180°
So, 61°+59°+<D=180°
120°+<D=180°
<D=180°-120°
<D=60°
So, the largest angle is <E= 61°
The longest side must be opposite to <E so, the side is DF
The second largest angle is <D=60° so, second side will be EF
The smallest angle is <F=59° so, third (shortest) side will be DE
Arranging from longest (at top) to shortest (at bottom)
DF
EF
DE
