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Alla [95]
3 years ago
13

GEOMETRY HELP! Celeste is constructing the perpendicular bisector of ST⎯⎯⎯⎯⎯ . Which set of instructions explains a correct way

to begin the construction? A) Place the compass point on point S and open the compass so that the pencil point is on the midpoint of the line segment. Draw an arc on each side of the segment. B) Place the compass point on the midpoint of the line segment and open the compass so that the pencil point is on point S. Draw an arc on each side of the segment. C) Place the compass point on point S and open the compass so that the pencil point is on the segment, but closer to point T than to point S. Draw an arc on each side of the segment. D) Place the compass point on point S and open the compass so that the pencil point is on the segment, but closer to point S than to point T. Draw an arc on each side of the segment.
Mathematics
1 answer:
Elan Coil [88]3 years ago
3 0

Answer:

The answer is C.

Step-by-step explanation:

Given the line segment ST. we have to give the instruction to construct the perpendicular bisector of line ST.

So to construct the perpendicular bisector of line our first step is to place the compass at one end of line and then adjust the compass more than half of line segment and draw the arc on each side of segment.

After that Keeping the same compass width, draw arcs from other end of line. Place scale where the arcs intersect, and draw the line segment.

So, the correct match is option C )  Place the compass point on point S and open the compass so that the pencil point is on the segment, but closer to point T than to point S. Draw an arc on each side of segment.

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y = \frac{-8}{3}x + 10 is the equation in slope intercept form

<em><u>Solution:</u></em>

Given points are (0, 10) and (3, 2)

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Let us first find the slope of line

<em><u>The slope of line is given as:</u></em>

m = \frac{y_2-y_1}{x_2-x_1}

Here,

(x_1, y_1) = (0, 10)\\\\(x_2, y_2) =(3,2)

<em><u>Substituting the values we get,</u></em>

m = \frac{2-10}{3-0}\\\\m = \frac{-8}{3}

<em><u>The equation of line in slope intercept form is given as:</u></em>

y = mx + c ------- eqn 1

Where, "m" is the slope of line and "c" is the y intercept

Substitute m = \frac{-8}{3} and (x , y) = (0, 10) in eqn 1

10 = \frac{-8}{3} \times 0 + c\\\\c = 10

Substitute\ m = \frac{-8}{3}\ and\ c = 10\ in\ eqn\ 1

y= \frac{-8}{3}x + 10

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Answer:

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Step-by-step explanation:

i hope this helped!

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Answer:

(1) Please find attached the graph of the data

(2) 160.396 m

(3) The correlation that exist is a straight line correlation

Step-by-step explanation:

The given data are;

Distance,         Time

(m),                    (s)  

50,                    6.1

100,                   12

150,                   18.3

200,                  25.2

250,                   31.7

(2)

Based on the linear regression formula, we have;

b = \dfrac{N\sum XY - \left (\sum X  \right )\left (\sum Y  \right )}{N\sum X^{2} - \left (\sum X  \right )^{2}}

b = \dfrac{5 \times 17215 - 93.3 \times 750}{5 \times 2156.03 -8704.89} = 7.758

a = \dfrac{\sum Y - b\sum X}{N}

a = \dfrac{750 - 7.7581 \times 93.3}{5}= 5.234

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y = 7.7581×x+5.234

When t = 20 s, we have

y = 7.7581*20+5.234 = 160.396 m

(3) The correlation that exist is a straight line correlation

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