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tresset_1 [31]
3 years ago
12

Mr. Jones is reading a mystery book to his sixth-grade English class. He reads 4 pages in 12 minutes.

Mathematics
2 answers:
Zinaida [17]3 years ago
7 0
The completed table would be :

4
8
12
16
kompoz [17]3 years ago
5 0
4, 8, 12, 16 I can’t see your table but I think these are the answers. :)
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Find 5 points that satisfy the equation y= 12+2x
Goshia [24]
We start by finding the intercept of the line: what does y equal when x=0? and what does x equal when y=0?
• intercept in x
y = 12 + 2x
0 = 12 + 2x
-12 = 2x
-6 = x
• intercept in y
y = 12 + 2x
y = 12 + 2(0)
y = 12 + 0
y = 12
Now we find three more points giving y a value and finding x
y = 12 + 2x
2 = 12 + 2x
2-12 = 2x
-10 = 2x
-5 = x

y = 12 + 2x
6 = 12 + 2x
6 - 12 = 2x
-6 = 2x
-3 = x

y = 12 + 2x
14 = 12 + 2x
14 - 12 = 2x
2 = 2x
1 = x

Notice how I gave y even numbers as values since we would have to divide with 2 at the end.

Sol. {(-6,0)(0,12)(-5,2)(-3,6)(1,14)}
8 0
3 years ago
Find the product of 8x93 using distributive property. Show the steps and the solution
lesya692 [45]

Explanation:

Distributive property: → a(b+c)=ab+ac

Multiply by the numbers from left to right.

93*8=744

Then, you can also divide into the numbers.

744/8=93

744/93=8

Product it's going to be multiply by the numbers, fractions, factors, and multiples.

Hope this helps!

Thanks!

Have a great day!

3 0
3 years ago
Read 2 more answers
A buyer went to the market to buy strawberries. He purchased 120 randomly selected strawberries from a vendor who claimed that n
mafiozo [28]

Answer:

z=\frac{0.333 -0.25}{\sqrt{\frac{0.25(1-0.25)}{120}}}=2.10  

p_v =P(z>2.10)=0.018  

At 5% of significance we can conclude that the true proportion of strawberries damage is higher than 0.25

Step-by-step explanation:

Data given and notation

n=120 represent the random sample taken

X=40 represent the number of strawberries damaged

\hat p=\frac{40}{120}=0.333 estimated proportion of strawberries damaged

p_o=0.25 is the value that we want to test

\alpha represent the significance level

z would represent the statistic (variable of interest)

p_v represent the p value (variable of interest)  

Concepts and formulas to use  

We need to conduct a hypothesis in order to test the claim that no more than 25% of his total harvest of strawberries was damaged.:  

Null hypothesis:p\leq 0.25  

Alternative hypothesis:p > 0.25  

When we conduct a proportion test we need to use the z statistic, and the is given by:  

z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}} (1)  

The One-Sample Proportion Test is used to assess whether a population proportion \hat p is significantly different from a hypothesized value p_o.

Calculate the statistic  

Since we have all the info requires we can replace in formula (1) like this:  

z=\frac{0.333 -0.25}{\sqrt{\frac{0.25(1-0.25)}{120}}}=2.10  

Statistical decision  

It's important to refresh the p value method or p value approach . "This method is about determining "likely" or "unlikely" by determining the probability assuming the null hypothesis were true of observing a more extreme test statistic in the direction of the alternative hypothesis than the one observed". Or in other words is just a method to have an statistical decision to fail to reject or reject the null hypothesis.  

The next step would be calculate the p value for this test.  

Since is a right tailed test the p value would be:  

p_v =P(z>2.10)=0.018  

At 5% of significance we can conclude that the true proportion of strawberries damage is higher than 0.25

6 0
3 years ago
-11p - -110 - -19p - 3 = 16​
amid [387]
The answer is P= 80/19
hope this helps
6 0
3 years ago
Determine the number and types of solutions for<br><br> 6m^2-3m-4=0
Anna11 [10]

Answer:

2 real solutions

Step-by-step explanation:

Remember this messy thing?

x=\dfrac{-b\pm\sqrt{b^2-4ac}}{2a}

The <em>quadratic formula</em>, as it's called, gives us the roots to any quadratic equation in standard form (ax² + bx + c = 0). The information on the <em>type</em> of roots is contained entirely in that bit under the square root symbol (b² - 4ac), called the <em>discriminant</em>. If it's non-negative, we'll have <em>real</em> roots, if it's negative, we'll have <em>complex roots</em>.

For our equation, we have a discrimant of (-3)² - 4(6)(-4) = 9 + 96 = 105, which is non-negative, so we'll have real solutions, and since quadratics are degree 2, we'll have exactly 2 real solutions.

4 0
3 years ago
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