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MakcuM [25]
3 years ago
14

Consider the equation 3p – 7 + p = 13. What is the resulting equation after the first step in the solution?

Mathematics
2 answers:
seraphim [82]3 years ago
7 0
4p-7=13
this is because you need to simplify the first side
if thats not the right answer, then is 4p=13
serg [7]3 years ago
4 0
Combine like terms

3p + p = 4p
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When a constant force acts upon an object, the acceleration of the object varies inversely with its mass. When a certain constan
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Answer:

a = 6m/s^2

Step-by-step explanation:

Given

When mass = 4kg; Acceleration = 15m/s²

Required

Determine the acceleration when mass = 10kg, provided force is constant;

Represent mass with m and acceleration with a

The question says there's an inverse variation between acceleration and mass; This is represented as thus;

a\ \alpha\ \frac{1}{m}

Convert variation to equality

a = \frac{F}{m}; Where F is the constant of variation (Force)

Make F the subject of formula;

F = ma

When mass = 4kg; Acceleration = 15m/s²

F = 4 * 15

F = 60N

When mass = 10kg; Substitute 60 for Force

F = ma

60 = 10 * a

60 = 10a

Divide both sides by 10

\frac{60}{10} = \frac{10a}{10}

a = 6m/s^2

<em>Hence, the acceleration is </em>a = 6m/s^2<em />

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3 years ago
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Solve: x + 1.5= 5.7<br> How do I solve this?
Mashutka [201]

Answer:

4.2

Step-by-step explanation:

5.7-1.5=4.2

4 0
3 years ago
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3 years ago
When a particular mass-spring system is started by stretching the spring 3 cm, one complete oscillation takes 4 seconds.
11Alexandr11 [23.1K]

Answer:

A. 5.16 s.

B. 5.66 s.

Step-by-step explanation:

A.

For a simple harmonic motion,

T = 2pi (sqrt * (l/g))

Given:

L1 = 3 cm

T1 = 4 s

L2 = 5 cm

T2 = ?

4 = 2pi*sqrt(3/g)

g = 7.4

At, L2,

T2 = 2pi*sqrt(5/7.4)

= 5.16 s.

B.

M1 = M1

M2 = 2*M1

For a simple harmonic motion,

T = 2pi (sqrt * (m/k))

4 = 2pi (sqrt * (M1/k))

M1/k = 0.405

Inputting the above values,

T2 = 2pi (sqrt * (2*M1/k))

= 2pi (sqrt * (2 * 0.405))

= 5.66 s.

4 0
3 years ago
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