(csc x-1)(csc x+1)=csc²x-1²=csc²x-1=(1/sin x)² -1=1/sin x² - sin²x/sin²x=
=(1-sin²x)/sin² x = cos² x/ sin² x = (cos x/sin x)²= (cot x)²
<u>Answer:</u>
Hence, Relation t is a function. The inverse of relation t is a function.
<u>Step-by-step explanation:</u>
We are given the relation as:
x: 0 , 2 , 4 , 6
y: -10 , -1 , 4 , 8
<em>Clearly from the y-values corresponding to the x-values we could see that each x has a single image (single y-value).</em>
Hence, the corresponding relation is a function.
Now we have to find whether the inverse of this relation is a function or not.
When we take the inverse of this function that is the y-values will behave as a pre-image and x-values as its image.
Hence we will see that corresponding to each y-value there is a unique image hence the inverse relation is also a function.
Hence, Relation t is a function. The inverse of relation t is a function.
Answer:
4/10
Step-by-step explanation:
1/10 + 3/10 = 4/10
Answer:
Area of the figure = 109 cm. square
Step-by-step explanation:
The radius of the semi circle is 12 ÷ 2 = 6 cm.
Area of the semi circle = 
The radius of the quarter circle is 6 cm.
Area of the quarter circle = 
The area of the rectangle = 12 × 2 = 24
The area of the figure = 18π + 9π + 24 = 108.78 ≅ 109 cm. square
Answer:
1 thousand i think hope this helps!
Step-by-step explanation: