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storchak [24]
3 years ago
5

Wind farm configuration is a significant issue as the upwind turbines generate maximal energy while creating wakes for downwind

turbines. One measurement of interest is the wake expression parameter, WEP. A random sample of 180 WEP measurements in rescaled units has mean 26.7 and standard deviation 17.7. (a) Compute a 95% confidence interval for the true mean WEP. (b) Does the true mean WEP differ from 30? Explain.
Mathematics
1 answer:
lord [1]3 years ago
7 0

Answer:

a) [24.114,29.2858]

b) Since 30 is not in the 95% confidence interval, there is a 95% probability that 30 is not the true mean WEP

Step-by-step explanation:

a)

The 95% confidence interval is given by the interval

\bf [ \bar x-z^*\frac{s}{\sqrt n}, \bar x+t^*\frac{s}{\sqrt n}]

where

\bf \bar x= 26.7 is the sample mean  

s = 17.7 is the sample standard deviation  

n = 180 is the sample size

Since the sample size is big enough, we can use the Normal N(0,1) to compute \bf z^* and it would be 1.96(*) (a value such that the area under the Normal curve outside the interval [-z, z] is 5% (0.05))

and our 95% confidence interval is

\bf [26.7-1.96*\frac{17.7}{\sqrt{180}}, 26.7+1.96*\frac{17.7}{\sqrt{180}}]=\boxed{[24.114,29.2858]}

(*)

This value can be computed in Excel with

<em>NORMINV(1-0.025,0,1)</em>

and in OpenOffice Calc with

<em>NORMINV(1-0.025;0;1)</em>

b)

Since 30 is not in the 95% confidence interval, there is a 95% probability that 30 is not the true mean WEP

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GaryK [48]

Answer:

d=10u

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Step-by-step explanation:

The shortest distance between the plane and Po is also the distance between Po and Q. To find that distance and the point Q you need the perpendicular line x to the plane that intersects Po, this line will have the direction of the normal of the plane n=(-2,-2,1), then r will have the next parametric equations:

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To find Q, the intersection between r and the plane T, substitute the parametric equations of r in T

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Substitute the value of \lambda in the parametric equations:

x=-5-2(-10/3)=-5+20/3=5/3\\y=-5-2(-10/3)=5/3\\z=-3+(-10/3)=-19/3\\

Those values are the coordinates of Q

Q(5/3,5/3,-19/3)

The distance from Po to the plane

d=\left| {\to} \atop {PoQ}} \right|=\sqrt{(\frac{5}{3}-(-5))^2+(\frac{5}{3}-(-5))^2+(\frac{-19}{3}-(-3))^2} \\d=\sqrt{(\frac{5}{3}+5))^2+(\frac{5}{3}+5)^2+(\frac{-19}{3}+3)^2} \\d=\sqrt{(\frac{20}{3})^2+(\frac{20}{3})^2+(\frac{-10}{3})^2}\\d=\sqrt{\frac{400}{9}+\frac{400}{9}+\frac{100}{9}}\\d=\sqrt{\frac{900}{9}}=\sqrt{100}\\d=10u

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-4x-2y=-12 <br>4x+8y=-24​
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Answer:

x = 6

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By adding both equations :-

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=》y = -36 ÷ 6

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putting the value of y in equation 2

=》4x + 8y = -24

=》4x + (8 × -6) = -24

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=》4x = 48 - 24

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<u> 1 |      2     -3   </u>

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         1  2  2  0

So the factorization is (x-2)(x²+x+2)=0 . When calculating the discriminant of the trinomial, it is concluded that it has no roots since the result is negative. So you only have one solution.

                   \bf{ 1^2-4(2)(2)=1-16=-15 < 0 \quad \Longrightarrow \quad x=2 }

\large\displaystyle\text{$\begin{gathered}\sf \pmb{3) \  6x^3+7x^2-9x+2=0 } \end{gathered}$}

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