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3 years ago

Algebra 2. Please help! I got 40% on my last try

Mathematics

2 answers:

bixtya [17]3 years ago

3 0

Maybe third one ( -2 -8)

marusya05 [52]3 years ago

3 0

Answer: x=-6 so it has to be the first option

Step-by-step explanation:

This is the answer upon dividing the polynomial.

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I need help ASAP. Thank you :)

kvasek [131]

m∠FDE = 52°

Solution:

Given data:

DE ≅ DF, CD || BE, BC || FD and m∠ABF = 116°

Sum of the adjacent angles in a straight line = 180°

m∠ABF + m∠CBF = 180°

116° + m∠CBF = 180°

m∠CBF = 64°

If CD || BE, then CD || BF.

Hence CD || BE and BE || FD.

Therefore BFCD is a parallelogam.

In parallelogram, Adjacent angles form a linear pair.

m∠CBF + m∠BFD = 180°

64° + m∠BFD = 180°

m∠BFD = 116°

Sum of the adjacent angles in a straight line = 180°

m∠BFD + m∠DFE = 180°

116° + m∠DFE = 180°

m∠DFE = 64°

we know that DE ≅ DF.

In triangle, angles opposite to equal sides are equal.

m∠DFE = m∠DEF

m∠DEF = 64°

sum of all the angles of a triangle = 180°

m∠DFE + m∠DEF + m∠FDE = 180°

64° + 64° + m∠FDE = 180°

m∠FDE = 52°

8 0

3 years ago

Neha used 4 bananas and 5 oranges in her fruit salad. Daniel used 7 bananas and 9 oranges. did Neha and Daniel use the same rati

Brilliant_brown [7]

No 4:5 is not 7:9

4:5 = 8:10

7:9 = 14:18

7 0

3 years ago

The basketball court at Cecil College is 50 feet by 94 feet. they need to buy fencing to go around the outside of the court in o

vitfil [10]

So the fencing perimiter is 70 by 114
perimiter=2 times width +2 times legnth
width=70
legnth=144
perimiter=70 times 2+114 times 2=140+228=368
needs to buy 368 feet

7 0

3 years ago

I need to find the missing numbers

const2013 [10]

Answer:

b11 = -14

b12 = 9

b13 = 8

Step-by-step explanation:

* Lets revise some notes to solve the problem

- Any matrix has a dimension m × n, where m is the number of rows

and n the number of columns

- We can add matrices with same dimensions

* Now lets solve the problem

∵ $B+\left[\begin{array}{ccc}15&-7&4\\0&1&2\end{array}\right]=\left[\begin{array}{ccc}1&2&12\\4&0&2\end{array}\right]$

- Let $B=\left[\begin{array}{ccc}b11&b12&b13\\b21&b22&b23\end{array}\right]$

∴ $\left[\begin{array}{ccc}b11&b12&b13\\b21&b22&b23\end{array}\right]+\left[\begin{array}{ccc}15&-7&4\\0&1&2\end{array}\right]=\left[\begin{array}{ccc}1&2&12\\4&0&2\end{array}\right]$

- Lets add and find the missing

* Lets start with the first rows

∵ b11 + 15 = 1 ⇒ subtract 15 from both sides

∴ b11 = -14

∵ b12 + -7 = 2 ⇒ add 7 to both sides

∴ b12 = 9

∵ b13 + 4 = 12 ⇒ subtract 4 from both sides

∴ b13 = 8

* Now lets start with the second rows

∵ b21 + 0 = 4

∴ b21 = 4 ⇒ given

∵ b22 + 1 = 0 ⇒ subtract 1 from both sides

∴ b22 = -1 ⇒ given

∵ b23 + 2 = 2 ⇒ subtract 2 from both sides

∴ b23 = 0 ⇒ given

5 0

3 years ago

If (3 + 453) (2-a)=-18-253 and the value of a

tiny-mole [99]

Answer:

a= 1183/456

Step-by-step explanation:

In pic

(Hope this helps can I pls have brainlist (crown) ☺️)

6 0

3 years ago