So average=(total of scores)/(number of tests)
needs at least average of 70
at least is represented as greater than or equal to or the sign (<u>></u>)
70<u>></u>(total)/(number oftests)
since we have 3 tests, we have to have 3 scores so
70<u>></u>(x+y+z)/3
he scored 85 and 60
70<u>></u>(x+85+60)/3 (doesn't matter which to subsitute)
70<u>></u>(x+145)/3
multiply obht sides by 3
210<u>></u>x+145
subtract 145 from both sides
65<u>></u>x
he needs to get at leas 65 on his third test
Answer:
median=81
mode=73
range=24
Step-by-step explanation:
median: Middle number from lowest to highest crossing one-off from either side.
(73,73,79,81,88,97)
mode:most popular number.
range: highest number minus lowest number.
Can i please get the equation so i can solve it
I will edit this after you put it
Ignore this \/
Under a dilation with center P and scale factor k, A' is the image of A. What is the value of k if PA = 7, and PA' = 28
Under a dilation with center P and scale factor k, A' is the image of A. What is the value of k if PA = 7, and PA' = 28?Under a dilation with center P and scale factor k, A' is the image of A. What is the value of k if PA = 7, and PA' = 28?Under a dilation with center P and scale factor k, A' is the image of A. What is the value of k if PA = 7, and PA' = 28?Under a dilation with center P and scale factor k, A' is the image of A. What is the value of k if PA = 7, and PA' = 28?Under a dilation with center P and scale factor k, A' is the image of A. What is the value of k if PA = 7, and PA' = 28?Under a dilation with center P and scale factor k, A' is the image of A. What is the value of k if PA = 7, and PA' = 28?Under a dilation with center P and scale factor k, A' is the image of A. What is the value of k if PA = 7, and PA' = 28?Under a dilation with center P and scale factor k, A' is the image of A. What is the value of k if PA = 7, and PA' = 28?Under a dilation with center P and scale factor k, A' is the image of A. What is the value of k if PA = 7, and PA' = 28?
I believe the answer is B.
Answer:
19404
Step-by-step explanation:
sum of arithmetic series is
Sn = n/2 (2a + (n-1)d)
or
Sn = n/2 (a + an)
a = 1st unit
an = last unit
d = difference
8-3 or 13-8 so d = 5
then first step is to find the value of n
an = a + (n-1)d
438 = 3 + (n-1)5
438 - 3 = 5n - 5
435 = 5n - 5
435 + 5 = 5n
440 = 5n
n = 440/5
n = 88
then we can find the sum
Sn = 88/2 (3 + 438)
S88 = 19404
