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Aleks04 [339]
3 years ago
8

In the trapezoid ABCD ( AB ∥ CD ) point M∈ AD , so that AM:MD=3:5. Line l ∥ AB and going trough point M intersects diagonal AC a

nd leg BC at points P and N respectively. Find: BC:BN
Mathematics
1 answer:
Ann [662]3 years ago
5 0

Answer:

BC : BN = 8 : 3

Step-by-step explanation:

Parallel lines divide any transversal into segments with the same ratio. That means ...

... BN : NC = AM : MD = 3 : 5

Since BC = BN + NC, the desired ratio is ...

... BC : BN = (BN+NC) : BN = (3+5) : 3

... BC : BN = 8 : 3

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A triangular sail has a base length of 2.5 meters.The area of the sail is 3.75 square meters.How tall is the sail?
love history [14]
Area of a triangle = 1/2 x base x height

--------------------------------------
Find Height :
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3.75  = 1/2 x 2.5 x height

3.75 = 1.25 x height 

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Answer: The height is 3 meters.
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Consider the following problem: a box with an open top is to be constructed from a square piece of cardboard, 3 feet wide, by cu
Alecsey [184]

Answer:

) See annex

b) See annex

x  =  0,5 ft

y =  2 ft   and

V = 2 ft³

Step-by-step explanation:  See annex

c) V = y*y*x

d-1) y = 3 - 2x

d-2) V = (3-2x)* ( 3-2x)* x   ⇒ V = (3-2x)²*x    

V(x) =( 9 + 4x² - 12x )*x    ⇒   V(x) = 9x + 4x³ - 12x²

Taking derivatives

V¨(x) = 9 + 12x² - 24x

V¨(x) = 0              ⇒   12x² -24x +9 = 0     ⇒  4x² - 8x + 3 = 0

Solving for x (second degree equation)

x =[ -b ± √b²- 4ac ] / 2a

we get    x₁  =  1,5       and    x₂ =  0,5

We look at y = 3 - 2x    and see that the value x₂ is the only valid root

then

x  =  0,5 ft

y =    2 ft   and

V = 0,5*2*2

V = 2 ft³

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Step-by-step explanation:

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3 years ago
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