Using a system of equation, we have that:
a)
- x, which is the cost of on-site service.
- y, which is the cost of at-store service.
- z, which is the cost of by-mail service.
b)
The system is:



c)
The cost of one on-site repair service is of $90.
Item a:
The variables are:
- x, which is the cost of on-site service.
- y, which is the cost of at-store service.
- z, which is the cost of by-mail service.
Item b:
On-site service costs <u>3 times as much as at-store service</u>, thus:

By mail service costs <u>$10 less than at-store</u> service, thus:

Last week, the shop completed <u>15 services on-site, 40 services at-store, and 5 services by mail for total sales of $3100</u>, thus:

The system is:



Item c:
- The cost of one on-site repair service is x.
- First, replacing the first two equations into the third, we find y, and then with it we find x.






Then

The cost of one on-site repair service is of $90.
A similar problem is given at brainly.com/question/24823220
Shortest is 3/4 longest is 1 1/2. 1 1/2 -3/4=3/4
<span>Check for the GCF first. ...Multiply the quadratic term and the constant term. ...Write down all the factors of the result, in pairs. ...<span>From this list, find the pair that adds to produce the coefficient of the linear term.</span></span>
Answer:
6-1
Step-by-step explanation:
Answer:

40 comic books
Step-by-step explanation:
Let x be the Jill comic books.
Given:
Jill sold half of her comic books and then bought sixteen more. She now has 36.



Therefore the algebraic equation of the given statement.
--------(1)
Now we solve above equation for x.
Subtract by 16 both side of the equation 1.


Multiply by 2 both side of the above equation.


Therefore, Jill had 40 comic books.