Answer:
d. $4,500
Explanation:
The computation of depreciation expense on the new equipment is shown below:-
For computing the depreciation expense on the new equipment first we need to find out the Depreciation per annum which is here below:-
Depreciation per annum = (Cost - Residual value) ÷ Life
= ($76,000 - $4,000) ÷ 8
= $72,000 ÷ 8
= $9,000
Depreciation for 1 year calendar (July 1 to Dec 31) = Depreciation per annum × 6 months ÷ Total number of months in a year
= $9,000 × 6 ÷ 12
= $4,500
So, the depreciation expenses for the year end up-to 31st Dec is $4,500
Your name of course, where you went to school, info on what your goals are that you want to obtain, work history, and what your good at.
The answer to the question is the least privilege policy.
The least privilege policy refers to a concept in computer security where users in a computer network are limited in terms of their ability to access things in the network according to the level of access needed for them to do their job. Thus, a person who works in Finance for example, would have a higher level of access compared to someone who works in Operations.
Answer:
A) R(x) = 120x - 0.5x^2
B) P(x) = - 0.75x^2 + 120x - 2500
C) 80
D) 2300
E) 80
Explanation:
Given the following :
Price of suit 'x' :
p = 120 - 0.5x
Cost of producing 'x' suits :
C(x)=2500 + 0.25 x^2
A) calculate total revenue 'R(x)'
Total Revenue = price × total quantity sold, If total quantity sold = 'x'
R(x) = (120 - 0.5x) * x
R(x) = 120x - 0.5x^2
B) Total profit, 'p(x)'
Profit = Total revenue - Cost of production
P(x) = R(x) - C(x)
P(x) = (120x - 0.5x^2) - (2500 + 0.25x^2)
P(x) = 120x - 0.5x^2 - 2500 - 0.25x^2
P(x) = - 0.5x^2 - 0.25x^2 + 120x - 2500
P(x) = - 0.75x^2 + 120x - 2500
C) To maximize profit
Find the marginal profit 'p' (x)'
First derivative of p(x)
d/dx (p(x)) = - 2(0.75)x + 120
P'(x) = - 1.5x + 120
-1.5x + 120 = 0
-1.5x = - 120
x = 120 / 1.5
x = 80
D) maximum profit
P(x) = - 0.75x^2 + 120x - 2500
P(80) = - 0.75(80)^2 + 120(80) - 2500
= -0.75(6400) + 9600 - 2500
= -4800 + 9600 - 2500
= 2300
E) price per suit in other to maximize profit
P = 120 - 0.5x
P = 120 - 0.5(80)
P = 120 - 40
P = $80
SORRY I NEED MORE INFO what exactly are you looking for?
