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Vesna [10]
3 years ago
13

La diferencia es la respuesta a un problema de....​

Mathematics
1 answer:
velikii [3]3 years ago
5 0

Answer:

sorry to say this but if you write the question in english it would be easy to understand

Step-by-step explanation:

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The cost of a game that was p dollars with a 15% off coupon online plus $1.99 for shipping
Shtirlitz [24]
(p - 0.15p) + 1.99

This is the equation to solve.

p minus 15% of p, plus 1.99 for shipping costs.
8 0
3 years ago
Consider the arithmetic series 3+7+11+ 15 +19+23+27+ .. and answer the questions which follow
neonofarm [45]

Answer:

T1 =3, S1 = 3

Step-by-step explanation:

i)T1 =3, S1 = 3

ii) S1 = T1

Hope it helps you in your learning process.

5 0
2 years ago
Read 2 more answers
The length of a rectangle is 5 in longer than its width. if the perimeter of the rectangle is 34 in , find its area.
shtirl [24]
Area(A)= lw
perimeter(P)= 2w+2l= 34in
length(l)= w+5 
width(w)= w

1/2 P= 17= w+l
17= w+(w+5)
17= 2w+5
2w=12
w=6 in

l= w+5
l= 6+5
l=11 in


A= lw= (11)(6)= 66in²

Answer:
Area of rectangle is 66 in².
3 0
3 years ago
huong and kathyrn each day impeoved their yards by planting rose bushes and ornamental grass. they bought their supplies from th
marta [7]

Answer:

One rose bush = $3

One bunch of ornamental grass = $4

Step-by-step explanation:

We can set up a system of equations to solve for this. Let cost of 1 rose bush be r and cost of 1 ornamental grass be g. Thus we can form 2 equations:

14r+7g=70\\5r+14g=71

We can multiply the first equation by -2 so that we can eliminate g. Thus, we have:

(*-2)14r+7g=70\\5r+14g=71\\-------\\-28r-14g=-140\\5r+14g=71\\--------\\-23r=-69\\r=\frac{-69}{-23}=3

Thus, 1 rose bush is $3. Now plugging in r = 3 into the first original equation, we can solve for g:

14r+7g=70\\14(3)+7g=70\\42+7g=70\\7g=70-42\\7g=28\\g=\frac{28}{7}=4

Thus, 1 bunch of ornamental grass is $4.

5 0
3 years ago
Solve sin 0 + 1 = cos20 on the interval 0 ≤ 0 < 2pi. Show work please!
yan [13]

Answer:

\theta=\frac{\pi}{2},\frac{3\pi}{2}\frac{2\pi}{3}\frac{4\pi}{3}

Step-by-step explanation:

You need 2 things in order to solve this equation:  a trig identity sheet and a unit circle.

You will find when you look on your trig identity sheet that

cos(2\theta)=1-2sin^2(\theta)

so we will make that replacement, getting everything in terms of sin:

sin(\theta)+1=1-2sin^2(\theta)

Now we will get everything on one side of the equals sign, set it equal to 0, and solve it:

2sin^2(\theta)+sin(\theta)=0

We can factor out the sin(theta), since it's common in both terms:

sin(\theta)(2sin(\theta)+1)=0

Because of the Zero Product Property, either

sin(\theta)=0 or

2sin(\theta)+1=0

Look at the unit circle and find which values of theta have a sin ratio of 0 in the interval from 0 to 2pi.  They are:

\theta=\frac{\pi}{2},\frac{3\pi}{2}

The next equation needs to first be solved for sin(theta):

2sin(\theta)+1=0 so

2sin(\theta)=-1 and

sin(\theta)=-\frac{1}{2}

Go back to your unit circle and find the values of theta where the sin is -1/2 in the interval.  They are:

\theta=\frac{2\pi}{3},\frac{4\pi}{3}

7 0
3 years ago
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