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rewona [7]
2 years ago
14

uppose that we have collected information on how much a sample of households spend on clothing per year. If we are 90% confident

that the true population mean will lie between $1,500 and $2,100, the chance that the population mean will either be less than $1,500 or above $2,100 is _____ %. Numeric Answer:
Mathematics
1 answer:
Verizon [17]2 years ago
5 0

Answer:

the chance that the population mean will either be less than $1,500 or above $2,100 is 10%

Step-by-step explanation:

We are 90% confident that the true population mean willl be between $1,500 and $2,100

This means that there is a 90% probability that the true population mean will be between $1,500 and $2,100.

So 100-90 = 10% probability that it is outside of this interval, that is, either be less than $1,500 or above $2,100.

So the correct answer is:

the chance that the population mean will either be less than $1,500 or above $2,100 is 10%

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Sveta_85 [38]

Answer:

57% to the nearest whole number

Step-by-step explanation:

That is (80/139.3) * 100

= 0.5743  * 100

= 57.43%.

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Unban_mh, there you go!.
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Read 2 more answers
1. (a) Use the integral test to show that P[infinity] n=1 1/n4 converges. (b) Find the 10th partial sum, s10, of the series P[in
scZoUnD [109]

Answer:

Step-by-step explanation:

a) \int\limits^{\infty} _1 {\frac{1}{n^4} } \, dn\\ =\frac{n^{-3} }{-3}

Substitute limits to get

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Thus converges.

b) 10th partial sum =

\int\limits^{10} _1 {\frac{1}{n^4} } \, dn\\ =\frac{n^{-3} }{-3}

=\frac{-1}{3} (0.001-1)\\= 0.333

c) Z [infinity] n+1 1 /x ^4 dx ≤ s − sn ≤ Z [infinity] n 1 /x^ 4 dx, (1)

where s is the sum of P[infinity] n=1 1/n4 and sn is the nth partial sum of P[infinity] n=1 1/n4 .

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3 years ago
What is 0.69696969 expressed as the quotient of two integers in simplest form?
timofeeve [1]

When written as the quotient of two integers,

           0.69696969  =  <em>69,696,969 / 100,000,000 .</em>

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4x-2y=12. Solve for y
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Step-by-step explanation:

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