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rewona [7]
3 years ago
14

uppose that we have collected information on how much a sample of households spend on clothing per year. If we are 90% confident

that the true population mean will lie between $1,500 and $2,100, the chance that the population mean will either be less than $1,500 or above $2,100 is _____ %. Numeric Answer:
Mathematics
1 answer:
Verizon [17]3 years ago
5 0

Answer:

the chance that the population mean will either be less than $1,500 or above $2,100 is 10%

Step-by-step explanation:

We are 90% confident that the true population mean willl be between $1,500 and $2,100

This means that there is a 90% probability that the true population mean will be between $1,500 and $2,100.

So 100-90 = 10% probability that it is outside of this interval, that is, either be less than $1,500 or above $2,100.

So the correct answer is:

the chance that the population mean will either be less than $1,500 or above $2,100 is 10%

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A sample of 16 small bags of the same brand of candies was selected. Assume that the population distribution of bag weights is n
Olegator [25]

Answer:

i) 2 - 1.64 \frac{0.1}{\sqrt{16}}= 1.959  

2 + 1.64 \frac{0.1}{\sqrt{16}}= 2.041  

So then the 90% confidence interval is given by (1.959, 2.041)

ii) Figure attached

iii) ME= 1.64 *\frac{0.1}{\sqrt{16}}= 0.041

Step-by-step explanation:

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The confidence interval is given by this formula:

\bar X \pm z_{\alpha/2} \frac{\sigma}{\sqrt{n}}}   (1)

And for a 90% of confidence the significance is given by \alpha=1-0.9=0.1, and \frac{\alpha}{2}=0.05. Since we know the population standard deviation we can calculate the critical value z_{0.05}= \pm 1.64

We know the folllowing data:

\bar X = 2 represent the sample mean

\sigma = 0.1 represent the population deviation

n =16 represent the sample size

Part i)

If we replace the values given into formula (1) we got:

2 - 1.64 \frac{0.1}{\sqrt{16}}= 1.959  

2 + 1.64 \frac{0.1}{\sqrt{16}}= 2.041  

So then the 90% confidence interval is given by (1.959, 2.041)

Part ii)

Figure attached. We have the illustration for the confidence interval obtained.

Part iii)

The margin of error is given by:

ME=z_{\alpha/2} \frac{\sigma}{\sqrt{n}}}

And if we replace we got:

ME= 1.64 *\frac{0.1}{\sqrt{16}}= 0.041

3 0
4 years ago
100 decreased by 50% and 150 decreased by 60%<br><br><br> Compare
sertanlavr [38]

Answer: 60% = 60/100 = 60 ÷ 100 = 0.6. 100% = 100/100 = 100 ÷ 100 = 1.

Step-by-step explanation: Decrease number by 60% of its value. Percentage decrease = 60% × 150 New value = 150

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Dr yang buys a violin for £13200 plus vat at 20% dr yang pays a deposit for the violin he then pays the rest of the cost in 12 e
Andre45 [30]

Answer:

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Step-by-step explanation:

Given that:

Cost of violin = 13200 plus VAT at 20%

Cost of violin = (100 + 20)% * 13200

Cost of violin = 1.20 * 13200 = £15,840

Instalment pay = (360 * 12) = 4320

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find the value of q for which point p(q,2) is the midpoint of the line segment joining the points q(-5,0) and r(-1,4)​
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Answer:

step by step solution:

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