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Colt1911 [192]
2 years ago
6

Can someone help with this math problem? 3 (x+6) = 27

Mathematics
1 answer:
Ainat [17]2 years ago
7 0

Answer:

x = 3

Step-by-step explanation:

Use distributive property: a(b +c) =(a*b) + (a*c)

3(x + 6) = 27

3*x + 3*6 = 27

3x + 18  = 27 {Subtract 18 from both sides}

3x + 18 -18 = 27 - 18

         3x    = 9  {Divide both sides by 3}

        3x/3 = 9/3

x = 3

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Assortative mating is a nonrandom mating pattern where individuals with similar genotypes and/or phenotypes mate with one anothe
scZoUnD [109]

Answer:

a) P(male=blue or female=blue) = 0.71

b) P(female=blue | male=blue) = 0.68

c) P(female=blue | male=brown) = 0.35

d) P(female=blue | male=green) = 0.31

e) We can conclude that the eye colors of male respondents and their partners are not independent.

Step-by-step explanation:

We are given following information about eye colors of 204 Scandinavian men and their female partners.

              Blue    Brown     Green    Total

Blue        78         23            13          114

Brown     19         23            12          54

Green     11           9             16          36

Total      108       55            41          204

a) What is the probability that a randomly chosen male respondent or his partner has blue eyes?

Using the addition rule of probability,

∵ P(A or B) = P(A) + P(B) - P(A and B)

For the given case,

P(male=blue or female=blue) = P(male=blue) + P(female=blue) - P(male=blue and female=blue)

P(male=blue or female=blue) = 114/204 + 108/204 − 78/204

P(male=blue or female=blue) = 0.71

b) What is the probability that a randomly chosen male respondent with blue eyes has a partner with blue eyes?

As per the rule of conditional probability,

P(female=blue | male=blue) = 78/114

P(female=blue | male=blue) = 0.68

c) What is the probability that a randomly chosen male respondent with brown eyes has a partner with blue eyes?

As per the rule of conditional probability,

P(female=blue | male=brown) = 19/54

P(female=blue | male=brown) = 0.35

d) What is the probability of a randomly chosen male respondent with green eyes having a partner with blue eyes?

As per the rule of conditional probability,

P(female=blue | male=green) = 11/36

P(female=blue | male=green) = 0.31

e) Does it appear that the eye colors of male respondents and their partners are independent? Explain

If the following relation holds true then we can conclude that the eye colors of male respondents and their partners are independent.

∵ P(B | A) = P(B)

P(female=blue | male=brown) = P(female=blue)

or alternatively, you can also test

P(female=blue | male=green) = P(female=blue)

P(female=blue | male=blue) = P(female=blue)

But

P(female=blue | male=brown) ≠ P(female=blue)

19/54 ≠ 108/204

0.35 ≠ 0.53

Therefore, we can conclude that the eye colors of male respondents and their partners are not independent.

7 0
3 years ago
HELP EASY PROBABLILITY QUESTION!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!
ella [17]

Answer:

0.43

Step-by-step explanation:

2+3+1+1=7

7*4+28==Area of full shape

(2*4)+(1*4)=12==Area of shaded shapes

12/28=0.428571>rounded up>0.43

3 0
3 years ago
Read 2 more answers
Suppose that F is an inverse square force field below, where c is a constant.
Andre45 [30]

Answer:

Forces in our Universe

Step-by-step explanation:

a)

First of all we have,

F(r) = \frac{cr}{|r|^{3} }

and,

r = xi+yj+zk

We need to define a function that allows us to find said change based on r, so one of the functions that shows that change is,

f(r) = - c /|r|

That is,

\nabla f = F

For this case F is a conservative field and the line integral is independent of the path. Thus, defining  P_{1} = (x_{1}, y_{1}, z_{1}) and P_{2} = (x_{2}, y_{2}, z_{2}) . So the amount of work on the movement of the object from P1 to P2 is,

W=\int\limits_c  {F} \, dr

W= f(P_{1}-P_{2})

W= \frac{c}{(x_{2}^2+ y_{2}^2+ z_{2}^2)^{1/2} } -\frac{c}{(x_{1}^2+ y_{1}^2+ z_{1}^2)^{1/2}}

W= c(\frac{1}{d1}-\frac{1}{d2}  )

2) The gravitational force field is given by,

F(r) =-\frac{mMGr}{ |r|^3}

The maximum distance from the earth to the sun is 1.52*10 ^ 8 km and the minimum distance is 1.47*10 ^ 8km. The mass values of the bodies are given by m = 5.97*10 ^ {24}kg, M = 1.99 *19 ^ {30}kg and the constant G is 6.67 * 10 ^{ -11 } \frac{Nm ^ 2}{kg^2}

In this way we raise the problem like this,

c= -mMG

W= -mMG (\frac{1}{1.52*10 ^ 8} -\frac{1}{1.47*10 ^ 8} )

W= -(5.95*10^{24})(1.99*10^{30})(6.67*10^{-11})(-2.2377*10^{-10})

W \approx 1.77*10^{35}}J

5 0
3 years ago
an isosceles triangle has congruent sides of 20cm. the base is 10cm. find the height of the triangle.​
dolphi86 [110]

Answer:

\large\boxed{A_\triangle=25\sqrt{15}\ cm^2}

Step-by-step explanation:

Look at the picture.

The formula of an area of a triangle:

A_\triangle=\dfrac{bh}{2}

<em>b</em><em> - base</em>

<em>h</em><em> - height</em>

<em />

We need a length of a height.

Use the Pythagorean theorem:

leg^2+leg^2=hypotenuse^2

We have:

leg=5,\ leg=h,\ hypotenuse=20

Substitute:

5^2+h^2=20^2

25+h^2=400             <em>subtract 25 from both sides</em>

h^2=375\to h=\sqrt{375}\\\\h=\sqrt{(25)(15)}\\\\h=\sqrt{25}\cdot\sqrt{15}\\\\h=5\sqrt{15}\ cm

Calculate the area:

A_\triangle=\dfrac{(10)(5\sqrt{15})}{2}=\dfrac{50\sqrt{15}}{2}=25\sqrt{15}\ cm^2

8 0
3 years ago
A plane descends 1000 ft while flying<br> 2.7 mi. What is the angle of descent?
Murrr4er [49]

Answer:

4.02°

Step-by-step explanation:

The angle of descent can be obtained using trigonometry ;

Since we have a right angled triangle ;

Let's use the relation:

Sin θ = opposite / hypotenus

Hypotenus = 2.7 miles

1 mile = 5280 feets

2.7 miles = (2.7 * 5280) = 14256 feets

Sin θ = 1000 / 14256

Sin θ = 0.0701459

θ = sin^-1(0.0701459)

θ = 4.0223674

3 0
3 years ago
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