calculate the potential energy of a 700kg squirrel that has leaped through the air with a height of 12m. (g=9.8m/s2)

Physics

1 answer:

Mnenie [13.5K]3 years ago

8 0

Answer:

P.E = 82320 joules

Explanation:

Given,

The mass of the squirrel, m = 700 Kg

The squirrel leaped to a height, h = 12 m

The acceleration due to gravity, g = 9.8 m/s²

The potential energy of a body is possessed by its height. It is given by the formula

P.E = mgh joules

Substituting the values in the above equation

P.E = 700 Kg x 9.8 m/s² x 12 m

= 82320 joules

The Potential Energy of the squirrel is, P.E = 82320 joules

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