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Inga [223]
3 years ago
11

calculate the potential energy of a 700kg squirrel that has leaped through the air with a height of 12m. (g=9.8m/s2)

Physics
1 answer:
Mnenie [13.5K]3 years ago
8 0

Answer:

 P.E = 82320 joules

Explanation:

Given,

The mass of the squirrel, m = 700 Kg

The squirrel leaped to a height, h = 12 m

The acceleration due to gravity, g = 9.8 m/s²

The potential energy of a body is possessed by its height. It is given by the formula

                               P.E = mgh   joules

Substituting the values in the above equation

                               P.E = 700 Kg x 9.8 m/s² x 12 m

                                     = 82320 joules

The Potential Energy of the squirrel is, P.E = 82320 joules

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Starting from rest, a solid sphere rolls without slipping down an incline plane. at the bottom of the incline, what does the ang
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Starting from rest, a solid sphere rolls without slipping down an incline plane. at the bottom of the incline, what does the angular velocity of the sphere depend upon? check all that apply. check all that apply. the angular velocity depends upon the length of the incline. the angular velocity depends upon the mass of the sphere. the angular velocity depends upon the radius of the sphere. the angular velocity depends upon the height of the incline
8 0
3 years ago
When the two surfaces of a thin film are parallel and the light is incident at some angle what fringes are formed? A. Circular B
lord [1]

Answer:

The correct option is;

A. Circular

Explanation:

Some of the light that impinges on the surface are reflected and the rest are transmitted to a different medium

At the surface of the next medium also, some of the light are transmitted while the others are reflected and refracted through the first medium

The speed of light (and hence the wavelength and color) refracted through the thin film is changed as the distance the refracted light travels through the thin film is increased as we move away from the point directly in the front view to some distance as the reflected light path from those distance to the eye is increased due to their inclination giving them a different wavelength which are all equal at a radial distance from the eye hence forming a circular fringes.

8 0
3 years ago
A spinning top spinning at 16rad/s takes 88.9s to come to a complete stop. Find the angular acceleration of the top.
AURORKA [14]

Answer:

The angular acceleration of the top is 0.18 rad/s²

Explanation:

Given;

angular velocity of the top, ω = 16 rad/s

time it takes to come to a complete stop, t = 88.9s

The angular acceleration of the top, is calculated as;

\alpha = \frac{\omega}{t}

α is the angular acceleration

ω is angular acceleration

t is the time

\alpha = \frac{\omega}{t}\\\\\alpha = \frac{16}{88.9}\\\\\alpha =0.18 \ rad/s^2

Therefore, the angular acceleration of the top is 0.18 rad/s²

5 0
3 years ago
A basketball player shoots toward a basket 4.9 m away and 3.0 m above the floor. If the ball is released 1.8 m above the floor a
Zolol [24]

Answer:

  v₀ = 6.64 m / s

Explanation:

This is a projectile throwing exercise

          x = v₀ₓ t

          y = y₀ + v_{oy} t - ½ g t²

In this case they indicate that y₀ = 1.8 m and the point of the basket is x=4.9m y = 3.0 m

         

the time to reach the basket is

        t = x / v₀ₓ

we substitute

        y- y₀ = \frac{ v_o \ x \ sin \theta  }{ v_o \ cos \theta} - \frac{1}{2} g \ \frac{x^2 }{v_o^2 \ cos^2 \theta }

        y - y₀ = x tan θ - \frac{ g \ x^2 }{ 2 \ cos^2 \theta } \ \frac{1}{v_o^2 }

         

we substitute the values

        3 -1.8 = 3.0 tan 60 - \frac{ 9.8 \ 3^2 }{2 \ cos^2 60 } \ \frac{1}{v_o^2}

        1.2 = 5.196 - 176.4 1 / v₀²

        176.4 1 / v₀² = 3.996

        v₀ = \sqrt{ \frac{ 176.4}{3.996} }

        v₀ = 6.64 m / s

6 0
3 years ago
Which of the options below has the correct number of each element for the compound?
slamgirl [31]

Answer:

there are no options buddy

7 0
3 years ago
Read 2 more answers
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