The final velocity is +15.0 m/s
Explanation:
The motion of the cart is a uniformly accelerated motion (=at constant acceleration), therefore we can use the following suvat equation:

where
v is the velocity at time t
u is the initial velocity
a is the acceleration
t is the time
For the cart in this problem, we have:
u = +3.0 m/s (initial velocity)
(acceleration)
t = 8.0 s (time)
Substituting, we find the final velocity:

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Answer:
we must multiply the speed value by 3.6
Explanation:
To reduce a magnitude from one unit to another, it must be multiplied by the equivalence in the order necessary so that the units do not change.
To reduce speed from m / s to km / h
we write the speed and the two conversion factors
v [m / s] [1 km / 1000m] [3600 s / 1h
v 3600/1000
v 3.6
therefore we must multiply the speed value by 3.6
This is not easy. We don't know what CS, US, CR, or UR is, and we don't know the end result. Basically, we have no clue. This question has to get pitched into the "No given information" bucket.
==> A piece-o-cake for light to get through.
==> Quite easy for light to get through.
==> Not very easy for light to get through.
==> Somewhat difficult for light to get through.
==> Pretty tough for light to get through.
==> Virtually impossible for light to get through.
==> Totally impossible for light to get through.
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Answer:
The work done by the crane is, W = 441000 J
The power of the crane is, p = 3675 watts
Explanation:
Given data,
The mass of the object, m = 900 kg
The object is lifted to the height, h = 50 m
The time taken to lift the mass, t = 2 min
= 120 s
The work done by the crane on the object is equal to the potential energy of the object at that height. It is given by the formula,
W = P.E = mgh joules
Substituting the values in the above equation
W = 900 kg x 9.8 m/s² x 50 m
= 441000 J
The work done by the crane is, W = 441000 J
The power of the crane,
P = W / t
= 441000 J / 120 s
= 3675 watts
Hence, the power of the crane is, p = 3675 watts