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3 years ago

A body cycles continously through a distance of 10km in 5 mins. calculate its average speed

Physics

1 answer:

stira [4]3 years ago

3 0

Answer:

distance=10km=10*1000=10000m

time=5min=5*60=300sec

average speed=distance/time

= 10000/300=33.33m/s

Explanation:

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Two blocks A and B have a weight of 11 lb and 5 lb , respectively. They are resting on the incline for which the coefficients of

Alchen [17]

Answer:

$\theta=10.20^{\circ}$

$\Delta l=0.10 ft$

Explanation:

First of all, we analyze the system of blocks before starting to move.

$\Sum F_{x}=P_{A}sin(\theta)+P_{B}sin(\theta)-F_{fA}-F_{fB}=0$

$\Sum F_{x}=11sin(\theta)+5sin(\theta)-0.16N_{A}-0.23N_{B}=0$

$11sin(\theta)+5sin(\theta)-0.16P_{A}cos(\theta)-0.23P_{B}cos(\theta)=0$

$11sin(\theta)+5sin(\theta)-0.16*11cos(\theta)-0.23*5cos(\theta)=0$

$16sin(\theta)-2.91cos(\theta)=0$

$tan(\theta)=0.18$

$\theta=arctan(0.18)$

$\theta=10.20^{\circ}$

Hence, the incline angle θ for which both blocks begin to slide is 10.20°.

Now, if we do a free body diagram of block A we have that after the block moves, the spring force must be taken into account.

$P_{A}sin(\theta)-F_{fA}-F_{spring}=0$

Where:

$F_{spring} = k\Delta l=2.1\Delta l$

$P_{A}sin(\theta)-0.16*11cos(\theta)-2.1\Delta l=0$

$\Delta l=\frac{11sin(\theta)-0.16*11cos(\theta)}{2.1}$

$\Delta l=0.10 ft$

Therefore, the required stretch or compression in the connecting spring is 0.10 ft.

I hope it helps you!

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4 years ago

A soldier throws a grenade horizontally from the top of a cliff. Which of the following curves best describes the path taken by

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Answer:

4. Parabola

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The motion of the flight of the grenade is a projectile motion, it's shape is best illustrated using a parabolic diagram.

It's not a circle as the path is not totally round.

It's not an ellipse as the path of motion is not a a completely bounded shape.

Its not a hyperbola as a hyperbola is an open curve with two branches.

Its a parabolic shape because a parabola has just one branch

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4 years ago

A body cycles continously through a distance of 10km in 5 mins. calculate its average speed​

A body cycles continously through a distance of 10km in 5 mins. calculate its average speed