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swat32
3 years ago
15

PHOTOGRAPHY PLEASE HELP!

Computers and Technology
1 answer:
BARSIC [14]3 years ago
8 0
1. Portfolios, folders, or drives
2. To make small touch ups and enhance your photos
3. People can steal your photos
4. Because they are trying to capture a story in a photo, and others can change the original intent of their work.
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Jump to Question: Fill in the blanks below: The flow of electricty is similar to the movement of water through a pipe. The movem
HACTEHA [7]

The answer is;

Current  

Voltage  

Power/Wattage  

Circuit

Water moving through pipes is like electricity flowing in a circuit. The flow of electricity is an actual flow of electrons. That movement of electrons is what is known as current. Think of current as the volume of water flowing through a water pipe. The electrons need some force or pressure to move, and so is water in a pipe. The voltage is that electromotive force; the pressure that pushes the electrons in a system. The power measured in Watts is the rate at which the energy is consumed. For the current to flow the circuit must be complete. Otherwise we cannot say that we have power if the circuit is not closed.

5 0
3 years ago
What was the first 1.0.1 version of openssl that was not vulnerable to heartbleed?
vovikov84 [41]
I suggest you to read OpenSSL changelogs to make it more clear. As there's not enough space to describe how it works. But heartbleed resistan version was 1.0.2, as I know.
5 0
3 years ago
Read 2 more answers
¿Cuál es la potencia de una lámpara de incandescencia que se conecta a la red de 220 V, sabiendo que tiene una resistencia de 50
Juliette [100K]

Answer:

  • <u>1,000W</u> (rounded to one significant figure)

Explanation:

I will answer in English.

The question is:

  • <em>What is the power of a filament lamp that connects to the 220 V network, knowing that it has a resistance of 50 ohms?</em>

<em />

<h2>Solution</h2>

<em />

<em>Power</em>, <em>voltage</em>, <em>resistance</em>, and current, are related by either of the following equations:

  • P = V × I
  • P = R × I²
  • P = V² / R

Where:

  • P is power in watts (W)
  • R is resistance in ohms (Ω)
  • V is voltage in volts (V), and
  • I is current in amperes (A)

Since you know the voltage (<em>220V</em>) and the resistance (<em>50Ω</em>), you can use the last equation:

  • P = V² / R
  • P = (220v)² / (50Ω)
  • P = 968 W

Since the magnitude 50Ω has one significant figure, your answer should be rounded to one significant figure. That is <u>1,000W.</u>

7 0
3 years ago
Every page on a website must be updated recently to consider the website updated/maintained
guajiro [1.7K]
Unmaintained. hope that helped
6 0
3 years ago
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Only numbers should go in the columns for Payload Size and Packet Size. The sizes are in bytes. Don't forget to account for the
Anna11 [10]

Answer:

Non-Payload Bytes sent are 1476(total) - 393 (payload) = 1083 bytes

1083 (non-payload) out of 1476(total) is 73.37 %

Non-Hello bytes sent are 1476(total) - 53(hello payload) = 1425 bytes

1425(non-hello) out of 1476(total) is 96.54 %

7 0
3 years ago
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