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EleoNora [17]
3 years ago
11

What mathematical operation do you use to solve to waist to hip ratio

Mathematics
1 answer:
scoray [572]3 years ago
5 0
Divition is the answer 
Ex. a/b = a:b
You might be interested in
What is the product?<br> 3x[-6 -14 -11 -9]
suter [353]

Answer:120

Step-by-step explanation:

calculate the sum of the negetive numbers 3x-40

=120

8 0
3 years ago
Using the information above regarding the proportion of agenda-less meetings, choose the correct conclusion for this hypothesis
ruslelena [56]

Answer: There is sufficient evidence to conclude that the proportion of agenda-less meetings is greater than 45%.

Step-by-step explanation:

Given: H_0:p=0.45 \\ H_a:p>0.45

The p-value for this hypothesis test is 0.025.

The level of significance is α=0.05

As p-value< α  ∵0.025< 0.05

[if p-value< α , we reject H_0]

then, we reject the null hypothesis.

i.e. We have sufficient evidence to support the alternative hypothesis.

Hence, the correct statement is : There is sufficient evidence to conclude that the proportion of agenda-less meetings is greater than 45%.

3 0
3 years ago
Find the inverse of the function f(x) = (x - 4) 2 - 5 if x ≥ 4.
Serggg [28]
Same here, we do a quick switcharoo on the variables first,

\bf \stackrel{f(x)}{y}=(x-4)^2-5\qquad inverse\implies \boxed{x}=\left( \boxed{y}-4 \right)^2-5&#10;\\\\\\&#10;x+5=(y-4)^2\implies \pm\sqrt{x+5}=y-4\implies \pm\sqrt{x+5}+4=y
6 0
3 years ago
. An object dropped from a height of 200 meters has a height, h(t), in meters after t seconds have lapsed, such that h(t) = 200
Veronika [31]

Answer:

t(h)= (h-200)/-4.9

The time to reach a height of 50 meters is 30.6 seconds

Step-by-step explanation:

To express t as a function of height (h) we must transform the equation below:

h=200-4.9t

h-200=-4.9t

(h-200)/-4.9=t

t(h)= (h-200)/-4.9

To find the time to reach a height of 50 meters, we must replace this value on the new equation:

t(h)=50-200/-4.9

t(h)= 30.612

The time to reach a height of 50 meters is 30.6 seconds

8 0
3 years ago
-/2 points
Rom4ik [11]

Answer:

Part 1) The domain of the quadratic function is the interval  (-∞,∞)

Part 2) The range is the interval  (-∞,1]

Step-by-step explanation:

we have

f(x)=-x^2+14x-48

This is a quadratic equation (vertical parabola) open downward (the leading coefficient is negative)

step 1

Find the domain

The domain of a function is the set of all possible values of x

The domain of the quadratic function is the interval

(-∞,∞)

All real numbers

step 2

Find the range

The range of a function is the complete set of all possible resulting values of y, after we have substituted the domain.

we have a vertical parabola open downward

The vertex is a maximum

Let

(h,k) the vertex of the parabola

so

The range is the interval

(-∞,k]

Find the vertex

f(x)=-x^2+14x-48

Factor -1 the leading coefficient

f(x)=-(x^2-14x)-48

Complete the square

f(x)=-(x^2-14x+49)-48+49

f(x)=-(x^2-14x+49)+1

Rewrite as perfect squares

f(x)=-(x-7)^2+1

The vertex is the point (7,1)

therefore

The range is the interval

(-∞,1]

6 0
3 years ago
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