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CaHeK987 [17]
3 years ago
15

At the beginning of the week the balance in your checkbook was $298.72. During the week you made a deposit of $425.69. You also

wrote checks for $29.72, $135.47, and $208.28. At the end of the week you received a letter from the bank indicating that they had deducted a $5.00 service charge from your account. How much is in your account at the end of the week? A. $350.94 B. $52.22 C. $345.94 D. $47.22
Mathematics
2 answers:
Jet001 [13]3 years ago
6 0
Answer is indeed choice C by creating an equation
Furkat [3]3 years ago
4 0

Hello!

Throughout this problem, we will add or subtract values from our original balance.

In your checkbook, there was 298.72 dollars, and then you deposited 425.69 dollars. The function you would do is addition.

$298.72 + 425.69 = $724.41

If you wrote a check, then the amount you wrote is removed from your checkbook.

$724.41 - $29.72 - $135.47- $208.28 = $350.94

Then, the bank deducted 5 dollars from your account.

$350.94 - $5.00 = $345.94

This leaves you with $345.94 at the end of the week.

Therefore, your answer is choice C, $345.94.

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SCORPION-xisa [38]

Answer:

3x^2y\sqrt(y)

Step-by-step explanation:

(\sqrt() means square root

its the 2nd one

4 0
2 years ago
A car has mass 1500 kg and is traveling at a speed of 35 miles/hour. what is its kinetic energy in joules? (Be sure to convert m
photoshop1234 [79]

Answer:

Factor by which kinetic energy increase = 4 times

Step-by-step explanation:

Given,

  • Mass of the car, v1 = 1500 kg
  • initial speed of car = 35 miles/h

                               =\dfrac{35\times 1609.34}{3600}\ m/s

                               = 15.64 m/s

Initial kinetic energy of the car is given by,

k_1\ =\ \dfrac{1}{2}.m.v_1^2

       =\ \dfrac{1}{2}\times 1500\times (15.64)^2\ joule

       = 183606.46 J

  • Final velocity of car v2 = 70 miles/hour

                                      =\dfrac{70\times 1609.34}{3600}

                                      = 31.29 m/s

So, final kinetic energy of car is given by

k_2\ =\ \dfrac{1}{2}.m.v_2^2

        =\ \dfrac{1}{2}\times 1500\times (31.29)^2

        = 734425.84 J

Now, the ratio of final to initial kinetic energy can be given by,

\dfrac{k_2}{k_1}=\ \dfrac{734425.84}{183606.46}

=>\ k_2\ =\ 4k_1                      

Hence, the kinetic energy will increase by 4 times.

7 0
3 years ago
The sixth term is 22 and the common difference is six Ward the question is what is the 15th term
NemiM [27]
<span>The sixth term is 22 and the common difference is is 6.</span>
4 0
3 years ago
Arrange the given steps in the correct order to find A and B if A and B are two sets where A – B = {1, 5, 7, 8}, B – A = {2, 10}
GarryVolchara [31]

Answer:

A = {1, 3, 5, 6, 7, 8, 9}

B = {2, 3, 6, 9, 10}

Step-by-step explanation:

Here as given in the question:

A – B = {1, 5, 7, 8}   ⇒ {1, 5, 7, 8} is in A not in B.

B – A = {2, 10} ⇒  {2, 10} is in B  not in A

A ∩ B = {3, 6, 9}   ⇒ {3, 6, 9} is BOTH in A and B.

Step 1:

Set A can also be expressed as :  A = (A - B) ∪ (A ∩ B)

Set A can also be expressed as :  B = (B - A) ∪ (A ∩ B)

Step 2:

Substituting the values of (A - B) and (B - A)

A = {1, 5, 7, 8} ∪ {3, 6, 9}

B = {2, 10} ∪ {3, 6, 9}.

Step 3:

Finding the UNION of the above two sets, we get:

A = {1, 3, 5, 6, 7, 8, 9}

B = {2, 3, 6, 9, 10}

5 0
3 years ago
Cargo ships arrive at a loading dock at a rate of 2 per day. The dock has the capability of handling 3 arrivals per day. How man
Vsevolod [243]

Answer:

4 days

Step-by-step explanation:

We need to use the probability functions of each of the intervals to know the Probability number and then use it in the expected value.

P(x>3 cargo ships) = 1-P(x<=3)

P(x>3) = 1-P(x<=3)

P(x>3) = 1-[P(x=0)+P(x=1)+P(x=2)+P(x=3)]

P(x>3) = 1 - [\frac{e^{-2}2^0}{01}+\frac{e^{-2}2^1}{11}+\frac{e^{-2}2^2}{21}+\frac{e^{-3}2^3}{31}]

P(x>3) = 1- [0.1353(1+2+2+1.33)]

P(x>3) = 1-0.856

P(x>3) = 0.1431

Als n=30, expected number is

E(x) =30*P(x>3)

E(x) = 30*0.1431

E(x) = 4.293

I expect 4.293 or 4 days per month the block being unable to hanlde all arriving ships

6 0
3 years ago
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