Answer:
The regular polygon that she should use is an equilateral triangle
Step-by-step explanation:
The parameters given are;
Interior angles = 0.5 × Exterior angles
Exterior angles of a regular polygon = 360/n
Sum of interior angles of a regular polygon = (n - 2) × 180
Where n = the number of sides
Therefore, the sum of exterior angles of a regular polygon = 360°
Hence we have;
(n - 2) × 180 = 360/2 = 180
n - 2 = 180/180 = 1
n = 1 + 2 = 3 which is a three sided regular polygon or an equilateral triangle
Therefore, the regular polygon that she should use is an equilateral triangle
A=h(b+c)
A/h=b+c
b=(A/h)-c
Answer: b=(A/h)-c
Jennifer SHE MAKES 12 Minutes
Max makes 11
And Joyce 10
Answer- Jennifer
The question has to do with scientific notation
<h3>What is scientific notation?</h3>
Scientific notation is the expression of a number in the form a × 10ⁿ where 1 ≤ a ≤ 10 and n is an integer.
<h3>How to simplify the expression?</h3>
Now to simplify the expression (9 × 10⁻¹³) - (6.3 × 10⁻¹⁵) both number have to have the same exponent to the power of 10.
So, re-writing, we have
(9 × 10⁻¹³) - (6.3 × 10⁻¹⁵) = (9 × 10⁻¹³) - (6.3 × 10⁻¹³ × 10⁻²)
= (9 × 10⁻¹³) - (6.3 × 10⁻² × 10⁻¹³ )
= (9 × 10⁻¹³) - (0.063 × 10⁻¹³ )
= (9 - 0.063) × 10⁻¹³ )
= 8.937 × 10⁻¹³
So, simplifying the expression (9 × 10⁻¹³) - (6.3 × 10⁻¹⁵) = 8.937 × 10⁻¹³
Learn more about scientific notation here:
brainly.com/question/28007630
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Answer:
5
Step-by-step explanation:
To find B and C prime, you must multiply them by .25, or 1/4.
B' =
(-2 x .25),(1 x .25)
I did mine in fraction form, because it will prove to be more useful in future mathematics.
B' = (1/2 , 1/4)
Repeat the process with C.
C' =
(14 x .25),(17 x .25)
C' =
(7/2 , 17/4)
You only need to focus on B and C because you are finding the length of B'C'.
The formula for distance is the square root of x to the sub of 2 minus x to the sub of 1 squared minus y to the sub of 2 minus y to the sub of 1 square.
x2 - x1 = 7/2 - 1/2 = 6/2 = 3 squared = 9
y2 - y1 = 17/4 - 1/4 = 16/4 = 4 squared = 16
16 + 9 = 25
Square root of 25 is 5.
Therefore, the distance is 5.