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MrRa [10]
3 years ago
13

What is the median of, 18, 16, 13, 10, 9.5, 8.5, 7.5, and six????

Mathematics
2 answers:
Katyanochek1 [597]3 years ago
8 0
18 |16 | 13 | 10 | 9.5 | 8.5 | 7.5 | 6
                      
9.75 is the FINAL answer
Evgesh-ka [11]3 years ago
7 0
You have to fist pot them in order 6,  7.5,  8.5,  9.5,  10,  13,  16,  18

so the middle numbers are 9.5 and 10 

add them together 9.5+10=19.5 then divide by 2 so 19.5/2=9.75  that is you answer
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The answer is 3.6 meter
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3 years ago
(x+7)(x-9)<br><br> Multiply Ponomials <br><br> show work please
Murrr4er [49]

Answer:

x(x-9)+7(x-9)

x²-9x+7x-63

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7 0
3 years ago
Two beach rental companies compared their sales from last weekend. Both companies rent out jet skis and kayaks, and they charge
nignag [31]

Answer:

To rent a jet ski you need to pay $50 and to rent a kayak you need to pay $20

Step-by-step explanation:

Since both shops charge the same amount for each kind of vehicle, we will assign variables to the their cost. The cost of a jet ski will be "x" and the cost of the kayak will be "y". Therefore we can create a system of equations as shown below:

Will's shop:

12*x + 9*y = 780

Fun Rentals:

7*x + 11*y = 570

\left \{ {{12x+ 9y=780} \atop {7x + 11y =570}} \right.\\

We can isolate "x" on the second equation, we have:

x = \frac{570 - 11y}{7}

Applying this value on the first equation:

12[\frac{570 - 11y}{7}] + 9y = 780\\\frac{6840 - 132y}{7} + 9y = 780\\\frac{6840 - 132y + 63y}{7} = 780\\ 6840 - 132y + 63y = 5460\\6840 - 69y = 5460\\69y = 1380\\y = 20

Applying the value of "y" we found on the "x" equation above, we have:x = \frac{570 - 11*20}{7}\\x = 50\\

Therefore to rent a jet ski you need to pay $50 and to rent a kayak you need to pay $20

7 0
3 years ago
What is 10/1 as a mixed number?
Mekhanik [1.2K]

10/1 as a mixed number is just 10

8 0
3 years ago
Read 2 more answers
HAAALLLLPPPP plz
valkas [14]

Answer:

the second one, B

Step-by-step explanation:

This is because in both numbers the decimal was moved back one.

8 0
3 years ago
Read 2 more answers
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