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cluponka [151]
3 years ago
7

Classify the following triangle as acute,obtuse, or right

Mathematics
1 answer:
igor_vitrenko [27]3 years ago
6 0

Answer:

Option B

Step-by-step explanation:

The following picture is a example of a "right triangle" or option B. Right triangles have 90 degree angles and look like a L, if you rotate the triangle to its base you would see that the 90 degree angle looks like a L making it a right triangle. It's not option A because acute angles have to be smaller then 90 degrees in order for it to be acute, it's not obtuse because the angle has to be greater then 90 degrees in order to be a obtuse triangle.

Hope this helps.

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For which pair of numbers is 4 a common factor.
dolphi86 [110]

Answer: 40 and 52

Step-by-step explanation:

40 =4 \times 10, 52=4\times 13, so both 40 and 52 have a factor of 4.

6 0
2 years ago
How many real number solutoins does the equation have? -8x^2 + 8x - 2 = 0
Yanka [14]

Answer:

one

Step-by-step explanation:

for general form : ax²+bx+c=0

delta = b²-4ac

so for this example delta is 8²-4×2×8 =0

we know if delta = 0 , we have just one real number solution

so the answer is 1

4 0
3 years ago
Solve.
Ksenya-84 [330]
<span>Solve.

x² + 4x + 4 = 18


​ A x=−4±3√ ​2

​ B x=2±3√ ​2

​ C x=4±9√ ​2

D x=−2±3√2



</span>x^2 + 4x + 4 = 18 \\  \\ x^2+4x+4-18= 0 \\  \\ x^2+4x-14=0 \\  \\ x_1_y_2=  \dfrac{-b\pm \sqrt{b^2-4ac} }{2a} \qquad a= 1\qquad b= 4\qquad c= -14 \\  \\  \\  x_1_y_2=  \dfrac{-4\pm \sqrt{4^2-4(1)(-14)} }{2(1)} \\  \\  \\  x_1_y_2=  \dfrac{-4\pm \sqrt{16-(-56)} }{2}  \\  \\  \\  x_1_y_2=  \dfrac{-4\pm \sqrt{72} }{2}  \\  \\  \\  x_1=  \dfrac{-4+ \sqrt{72} }{2} \qquad\qquad x_2=  \dfrac{-4+ \sqrt{72} }{2}\\  \\  \\  x_1=  \dfrac{-4+ \sqrt{2^3*3^2} }{2} \qquad\qquad x_2=  \dfrac{-4- \sqrt{2^3*3^2} }{2}
<span>
</span>x_1=  \dfrac{-4+2*3 \sqrt{2} }{2} \qquad\qquad x_2=  \dfrac{-4- 2*3\sqrt{2} }{2} \\  \\  \\ x_1=  \dfrac{-4+6 \sqrt{2} }{2} \qquad\qquad x_2=  \dfrac{-4- 6\sqrt{2} }{2} \\  \\  \\ x_1=  \dfrac{-4}{2} + \dfrac{6 \sqrt{2} }{2} \qquad\qquad x_2=   \dfrac{-4}{2}- \dfrac{ 6\sqrt{2} }{2} \\  \\  \\  x_1= -2 + 3 \sqrt{2} \qquad\qquad\quad  x_2=  -2- 3\sqrt{2}  \\  \\  \\ \boxed{x=   -2\pm 3\sqrt{2} }  \to D)<span>
</span>
7 0
4 years ago
Read 2 more answers
Assume that the GMAT scores across the U.S. follow a bell shaped distribution (symmetric and unimodal) with mean 549 and standar
blondinia [14]

Answer:

The GMAT score corresponding to the 16th percentile is 473.

Step-by-step explanation:

Empirical Rule.

The Empirical Rule states that, for a normally distributed random variable:

Approximately 68% of the measures are within 1 standard deviation of the mean.

Approximately 95% of the measures are within 2 standard deviations of the mean.

Approximately 99.7% of the measures are within 3 standard deviations of the mean.

68% of the measures within 1 standard deviation of the mean.

This means that they are between the 50 - (68/2) = 50 - 34 = 16th percentile(one standard deviation below the mean) and the 50 + (68/2) = 50 + 34 = 84th percentile(one standard deviation above the mean).

In this question:

Mean of 549, standard deviation of 76.

16th percentile:

One standard deviation below the mean, so 549 - 76 = 473.

The GMAT score corresponding to the 16th percentile is 473.

5 0
3 years ago
One angle in an isosceles triangle is 25 degrees. What are the other possible angle measurements?
sweet [91]

(180 - 25) \div 2 = 77.5
Since it's an isosceles triangle, it means there's two angles' measurements are the same.

Answer : The other possible angle measurements are 25 degrees and 77.5 degrees.

Hope this helps. - M
4 0
3 years ago
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