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timama [110]
3 years ago
12

Factorise this expression as fully as possible 2x^2+6x

Mathematics
1 answer:
AURORKA [14]3 years ago
3 0

Answer:

(Factor out 2x from the expression)

2x (x +3)

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When a number is even, it's often easiest to start by dividing by 2 to find factors.

Since 48 ÷ 2 . is 24, we know that 2 and 24 are factors of 48 so we write 2 and 24 at the bottom of the branches.

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Since 12 ÷ 2 is 6, we know that 2 and 6 are factors of 12. This means that we write 2 and 6 at the bottom of the branches. Next, we circle any prime factors in the factor tree. Since 2 is a prime number, we circle 2 but draw two new branches coming down from 6 because it's not prime.

Since 6 ÷ 2 is 3, we know that 2 and 3 are factors of 6 so we write 2 and 3 at the bottom of the branches. Next, we circle any prime factors in the factor tree. Since both 2 and 3 are prime meaning that the only factors they have are 1 and the number itself, we circle both 2 and 3.

Since we have circles at the bottom of all of the branches, we are finished.

So the prime factorization of 48 is 2 × 2 × 2 × 2 × 3.

Notice that the factor 2 is repeated 4 times. In this case, we can rewrite the prime factorization of 48 using exponents as 2^{4} x 3

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