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timama [110]
3 years ago
12

Factorise this expression as fully as possible 2x^2+6x

Mathematics
1 answer:
AURORKA [14]3 years ago
3 0

Answer:

(Factor out 2x from the expression)

2x (x +3)

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3x+8=2x+21<br> X=?<br> (all working out needed)
Dahasolnce [82]

Answer:

x=13

Step-by-step explanation:

3x=2x+21−8

3x=2x+13

3x−2x=13

x=13

8 0
3 years ago
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Iestieasurement
Makovka662 [10]
The clock is showing 7:55 AM
Since it’s 12 minutes behind then the time would be 7:43 AM
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3 years ago
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John accepted a reduction of 15% on his salary when his company was not doing well. Now his company's financial position has imp
o-na [289]
To reverse a percentage decrease you divide it by the decrease (+ 100%)
For example we will pick the number, 100, which is decreased by 15% to 85.

To make 85 back to 100 we divide it by the decrease (1-0.15):
85 / 0.85 = 100

To find out how much 85 increased to get back to 100, we do:
15 / 85 = 0.1765 = %17.65

15 is the reduction/difference, and 85 is the with reduction total.

Because percentages stay the same, this is applicable to any numbers, from this, we know that whenever something is reduced by 15% - when restored to it's original is increased by %17.65

The answer is %17.65


6 0
3 years ago
The International Air Transport Association surveys business travelers to develop quality ratings for transatlantic gateway airp
motikmotik

Answer:

The 95% confidence interval for the population mean rating is (5.73, 6.95).

Step-by-step explanation:

We start by calculating the mean and standard deviation of the sample:

M=\dfrac{1}{n}\sum_{i=1}^n\,x_i\\\\\\M=\dfrac{1}{50}(6+4+6+. . .+6)\\\\\\M=\dfrac{317}{50}\\\\\\M=6.34\\\\\\s=\sqrt{\dfrac{1}{n-1}\sum_{i=1}^n\,(x_i-M)^2}\\\\\\s=\sqrt{\dfrac{1}{49}((6-6.34)^2+(4-6.34)^2+(6-6.34)^2+. . . +(6-6.34)^2)}\\\\\\s=\sqrt{\dfrac{229.22}{49}}\\\\\\s=\sqrt{4.68}=2.16\\\\\\

We have to calculate a 95% confidence interval for the mean.

The population standard deviation is not known, so we have to estimate it from the sample standard deviation and use a t-students distribution to calculate the critical value.

The sample mean is M=6.34.

The sample size is N=50.

When σ is not known, s divided by the square root of N is used as an estimate of σM:

s_M=\dfrac{s}{\sqrt{N}}=\dfrac{2.16}{\sqrt{50}}=\dfrac{2.16}{7.071}=0.305

The degrees of freedom for this sample size are:

df=n-1=50-1=49

The t-value for a 95% confidence interval and 49 degrees of freedom is t=2.01.

The margin of error (MOE) can be calculated as:

MOE=t\cdot s_M=2.01 \cdot 0.305=0.61

Then, the lower and upper bounds of the confidence interval are:

LL=M-t \cdot s_M = 6.34-0.61=5.73\\\\UL=M+t \cdot s_M = 6.34+0.61=6.95

The 95% confidence interval for the mean is (5.73, 6.95).

4 0
4 years ago
At Rose State College Allison Wells received the following grades her accounting class 93, 60, 78, 89 ,78 and 82 Allison's instr
Lunna [17]

so you drop the 60.
93 + 78 + 89 + 78 + 82 = 420
420 \div 5 = 84

so the answer is 84
7 0
3 years ago
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