Answer:
yes a
Step-by-step explanation:
(-a^3b^2*-a^-2b^-3)^-2/2a^2b^-3
= a^4b^9/2a^8b^4
=b^5/2a^4
so your answer is b^5/2a^4
V(cylinder)=πR²H
Radius of the cylinder R=x, height of the cylinder H=y.
We can write for the cylinder
V(cylinder)=πx²y
V(cone) =(1/3)πr²h
Radius of the cone r=2x.
We can write for the cone
V(cone)= (1/3)π(2x)²h=(1/3)π *4*x²h
V(cylinder) =V(cone)
πx²y=(1/3)π *4*x²h
y=(4/3)*h
h=(3/4)*y
The answer is 10
8+(8)2÷4·2
8+16÷4·2 4·2=8 then 16÷8
8+2=10
just use PEMDAS
Answer:
(a) mean = 377.5ml. standard deviation = 4.33
(b) 0.333
(c) 384.25 ml
Step-by-step explanation:
(a)The mean:
The standard deviation:
(b)
(c)P(x > m) = 0.95
So the volumn of shampoo should be 384.25ml to exceed 95% of containers.
