Ask question

Ask question

All categories

2 years ago

9

In a 3-digit number, the hundreds digit is one more than the one's digit, and the tens digit is twice the hundreds digit. If the

sum of the digits is 11, find the number. PLEASE TELL ME THE CORRECT EQUATION!

1 answer:

arsen [322]2 years ago

8 0

3 digits
Sum (adding) = 11
362

You might be interested in

6) Maria bought seven boxes. A week later

Musya8 [376]

Answer:

37

Step-by-step explanation:

Maria started with x boxes.

When she bought 7 boxes, she has (x+7).

Half of her boxes are destroyed (x+7)/2.

Half of her boxes left (x+7)/2.

And

(x+7)/2 = 22

x+7=44

x= 44 -7 = 37

4 0

3 years ago

Find all roots<br> x^4-29x^2+100=0;-5

jeka57 [31]

Answer:

how about you go fلللاااuاااcلللk urself

3 0

3 years ago

Solve s = rθ for θ.<br><br> A) θ = rs <br> B) θ = r/s<br> C) θ = s/r<br> D) θ = 1/rs

meriva

Dividing both sides by r

=s/r

5 0

3 years ago

Read 2 more answers

The hypotenuse of a right triangle is 1 centimeter longer than one side and 4 centimeters longer than three times the other side

snow_tiger [21]

Answer:

$Hypotenuse = 25cm$

$Opposite = 24cm$

$Adjacent = 7cm$

Step-by-step explanation:

Represent:

The opposite with a
The adjacent with b
The hypotenuse with c

Given that:

$c = 1 + a$

$c = 4 + 3b$

Required

Solve for a, b and c

$c = c$

So, we have:

$1 + a = 4 + 3b$

Subtract 1 from both sides

$a = 4 -1 + 3b$

$a = 3 + 3b$

Apply Pythagoras Theorem

$c^2 = a^2 + b^2$

Substitute 3 + 3b for a and 4 + 3b for c

$(4 + 3b)^2 = (3 + 3b)^2 + b^2$

Open brackets

$16 + 12b+12b+9b^2 = 9 + 9b+9b+9b^2 +b^2$

$16 + 24b+9b^2 = 9 + 18b+10b^2$

Collect Like Terms

$10b^2 - 9b^2 + 18b - 24b + 9 - 16 = 0$

$b^2 - 6b -7 = 0$

Expand

$b^2 +b-7b-7=0$

Factorize:

$b(b+1)-7(b+1) =0$

$(b-7)(b+1) = 0$

Split:

$b - 7 = 0\ or\ b+1=0$

$b = 7\ or\ b=-1$

But the adjacent of a triangle can't have a negative measurement.

So:

$b = 7$

Recall that:

$c = 4 + 3b$

$a = 3 + 3b$

Substitute 7 for b in the above expressions

$c = 4 + 3 * 7$

$c = 4 + 21$

$c = 25$

$a = 3 + 3 * 7$

$a = 3 + 21$

$a = 24$

Hence, the dimensions of the triangle are:

$Hypotenuse = 25cm$

$Opposite = 24cm$

$Adjacent = 7cm$

5 0

2 years ago

Help me out please :((((((((

My name is Ann [436]

Answer: I think b

Step-by-step explanation:

5 0

2 years ago