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Vladimir [108]
3 years ago
14

A colored chip is yellow on one side and red on the other. The chip was flipped 50 times and landed red side facing up 21 times.

What is the relative frequency of the chip landing with the red side facing up?
A) 42%
B) 58%
C) 68%
D) 72%
Mathematics
1 answer:
meriva3 years ago
6 0

<u>Answer:</u>

42%

<u>Step-by-step explanation:</u>

We know that the number of times red side is faced up = 21; and

the total number of times colored chip is thrown = 50

Frequency of red side = (No of times red side is faced up / Total number of times colored chip is thrown)   * 100%

Frequency of red side = (21 / 50) * 100% = 0.42 * 100 = 42%

Therefore, the relative frequency of the chip landing with the red side facing up is 42%.

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fredd [130]

Answer:

B

Step-by-step explanation:

8 0
3 years ago
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AleksandrR [38]

Answer:

Step-by-step explanation:

x18y32 x18y ​x6y4 ​x6y32

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7 0
3 years ago
A cab company charges $0.80 per mile plus $2 for tolls. Melissa has at most $16 to spend on her cab fare. Write and solve an ine
Anna35 [415]

Answer:

The maximum distance is 17.5 miles

No she can't make to the airport.

Step-by-step explanation:

Given the cab charges $0.8 per mile and $2 for tolls.

let the miles travelled by melissa be x.

The total charge is $(0.8*x+2)

Now given that she can spend a maximum of $16

so the inequality is

0.8*x+2\leq 16

0.8*x\leq 14

x\leq \frac{14}{0.8}

x\leq 17.5

Therefore the maximum distance she can travel is 17.5 miles

Since the distance to airport is 25 miles which is greater than 17.5 miles she cannot afford the cab.

3 0
4 years ago
Please see attachment
Dafna11 [192]

Answer:

a) The value of absolute minimum value = - 0.3536  

b) which is attained at   x = \frac{1}{\sqrt{2} }  

Step-by-step explanation:

<u>Step(i)</u>:-

Given function

                       f(x) = \frac{-x}{2x^{2} +1}     ...(i)

Differentiating equation (i) with respective to 'x'

                     f^{l} = \frac{2x^{2} +1(-1) - (-x) (4x)}{(2x^{2}+1)^{2}  }   ...(ii)

                    f^{l}(x) = \frac{2x^{2}-1}{(2x^{2}+1)^{2}  }

Equating Zero

                   f^{l}(x) = \frac{2x^{2}-1}{(2x^{2}+1)^{2}  } = 0

                 \frac{2x^{2}-1}{(2x^{2}+1)^{2}  } = 0

                2 x^{2}-1 = 0

               2 x^{2} = 1

             x^{2}  = \frac{1}{2}

             x = \frac{-1}{\sqrt{2} }  , x = \frac{1}{\sqrt{2} }

<u><em>Step(ii):</em></u>-

Again Differentiating equation (ii) with respective to 'x'

f^{ll}(x) = \frac{(2x^{2} +1)^{2} (4x) - 2(2x^{2} +1) (4x)(2x^{2}-1) }{(2x^{2}+1)^{4}  }

put

      x = \frac{1}{\sqrt{2} }

f^{ll} (x) > 0

The absolute minimum value at   x = \frac{1}{\sqrt{2} }

<u><em>Step(iii):</em></u>-

The value of absolute minimum value

                         f(x) = \frac{-x}{2x^{2} +1}

                       f(\frac{1}{\sqrt{2} } ) = \frac{-\frac{1}{\sqrt{2} } }{2(\frac{1}{\sqrt{2} } )^{2} +1}

         on calculation we get

The value of absolute minimum value = - 0.3536      

<u><em>Final answer</em></u>:-

a) The value of absolute minimum value = - 0.3536  

b) which is attained at   x = \frac{1}{\sqrt{2} }    

3 0
3 years ago
4x-5y=13
love history [14]
Hello : 
<span>4x-5y=13...(1)
x+5y=-3...(2)
(1)+(2) : 5x = 10
x=2
subsct in (2) : 2+5y = -3
5y =-5
y = -1

</span>
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