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grandymaker [24]
2 years ago
13

1.2 x 10^19 x 5.88 x 10^12

Mathematics
1 answer:
Lapatulllka [165]2 years ago
7 0

9514 1404 393

Answer:

  7.056 × 10^31

Step-by-step explanation:

The applicable rule of exponents is ...

  (10^a)(10^b) = 10^(a+b)

__

  (1.2\times10^{19})\times(5.88\times10^{12})=(1.2\cdot5.88)\times10^{19+12}\\\\=\boxed{7.056\times10^{31}}

As you know, the commutative and associative properties of multiplication let you rearrange the order of the product to any convenient form. Here it is convenient to group the mantissas together and the powers of 10 together.

__

<em>Additional comments</em>

This is a product your scientific or graphing calculator can produce for you. Likely it will display the result in scientific notation because it won't have enough display digits to show you the product any other way. For smaller numbers, you can set the display mode to give you scientific notation.

If you choose to use a spreadsheet to perform this calculation, the numbers would be entered as 1.2e19 and 5.88e12. The result will be something like 7.056e31. You may have to format the display to show 3 decimal places.

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8 0
3 years ago
Write N as a discrete exponential function of t of the form N(t)=A(1+r)t. (HINT: You will need to find (1+r), where r is the rat
Whitepunk [10]

Answer:

N(t)=84(1+0.0405)^t.

Step-by-step explanation:

We have been given that N(11)=130 and N(0)=84. We are asked to write N as a discrete exponential function of t of the form N(t)=A(1+r)^t.

Using our given information, we can set an equation as:

N(0)=A(1+r)^0

84=A*1

84=A

Using our given information, we will get:

N(11)=A(1+r)^{11}

Substitute the given values:

130=84(1+r)^{11}

\frac{130}{84}=\frac{84(1+r)^{11}}{84}

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Switch sides:

(1+r)^{11}=1.5476190476190476

Take 11th root of both sides:

\sqrt[11]{(1+r)^{11}}=\sqrt[11]{1.5476190476190476}

1+r=1.04050024747304

r=1.04050024747304-1

r=0.04050024747304

r\approx 0.0405

Therefore, our required function would be N(t)=84(1+0.0405)^t.

5 0
2 years ago
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Answer:

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