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3 years ago

Explain why the equation 2(3x-5)=6x+8 has no solutions.

Mathematics

1 answer:

serious [3.7K]3 years ago

4 0

Answer:

see explanation

Step-by-step explanation:

Given

2(3x - 5) = 6x + 8 ← distribute left side

6x - 10 = 6x + 8 ( add 10 to both sides )

6x = 6x + 18 ( subtract 6x from both sides )

0 = 18 ← not possible

This indicates the equation has no solution

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The question is............

irina1246 [14]

A(n,s)=(ns^2)/(4tan(180/n)), n=number of sides, s=side length

A(8,4.6)=(8*4.6^2)/(4tan22.5)

A(8,4.6)=42.32/tan22.5 m (exact)

A(8, 4.6)≈102.17 m^2 (to nearest hundredth of a square meter)

7 0

3 years ago

HELP QUICK

noname [10]

Answer:

84ft

Step-by-step explanation:

w = 2/3(L)

if 280 feet of fencing can enclose the garden,therefore the perimeter is 280 feet

perimeter = 2L + 2W

but W=2/3(L)

therefore, perimeter = 2L + 2(2/3L)

P= 2L + 4/3(L)

P= 10/3(L)

but P= 280

therefore 280= 10/3(L)

L = (3×280)÷10

L= 84 feet

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3 years ago

carlas cab ride cost 22$ she wants to leave a 15% tip what is her tip? what is her total cost for the cab ride?

Semenov [28]

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3 years ago

Read 2 more answers

Find the equation of the circle with a diameter whose end points are (-1,-2) and (-3,2)

Sergeeva-Olga [200]

Answer:

The equation of the circle with a diameter whose end points are (-1,-2) and (-3,2) is

$x^{2} +y^{2}+4x-1=0$

Step-by-step explanation:

Explanation:-

Step 1:-

The equation of the circle having center and radius is

$(x-h)^2+(y-k)^2=r^2$

here center is (h,k) and radius is r

Given diameter whose end points are (-1,-2) and (-3,2)

The diameter of the circle is passing through the center of the circle

so center of the circle = midpoint of two end points

$(\frac{-1 +(-3) }{2} ,\frac{-2+2 }{2} )$

$(-2,0)$

therefore center (h,k) = (-2,0)

Step 2:-

we have to find the radius of the circle

the radius of the circle = the distance from center to the one end point

i.e., C P = r

Given one end point is P(-3,2) and center C(-2,0)

The distance formula of two points are

$\sqrt{(x_{2}-x_{1} ) ^{2}+ (y_{2}-y_{1} ) ^{2}}$

$r=\sqrt{{(-3)-(-1) ) ^{2}+ (2-(-2)) ^{2}}$

$r=\sqrt{5}$

Step 3:-

center (h,k) = (-2,0) and

radius $r=\sqrt{5}$

The standard form of circle equation

$(x-h)^2+(y-k)^2=r^2$

$(x-(-2))^2+(y-0)^2=\sqrt{5} ^2$

on simplification is

$x^{2} +y^{2}+4 x-1=0$

5 0

3 years ago

Which is a correct first step for solving this equation

rosijanka [135]

Answer:

see explanation

Step-by-step explanation:

given

- 3x + 2 - 5x - 7 = 4x + 2

The first step is to simplify the left side by collecting like terms

- 8x - 5 = 4x + 2

5 0

4 years ago