We are given dimensions of model and actual figure.
model: 9.5cm actual : 30.5m.
We need to find the length of actual shape for the scale factor 5cm.
Let us assume actual length be x m.
Let us set a proportion now.
<h3>5 : x = 9.5 : 30.5</h3>Let us convert proportion into fractions.
On cross multiplying, we get
9.5x = 5× 30.5
9.5x = 152.5.
On dividing both sides by 9.5, we get
x=16.05.
<h3>Therefore, the scale factor for a model is 5cm= 16.05 m.</h3>
Answer:
The mean of the sampling distribution of the sample proportions is 0.82 and the standard deviation is 0.0256.
Step-by-step explanation:
The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean and standard deviation
, the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean
and standard deviation
.
For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.
For proportions, the mean is and the standard deviation is
In this problem, we have that:
.
So
The mean of the sampling distribution of the sample proportions is 0.82 and the standard deviation is 0.0256.
Answer:
8. -3, 16
9. -3, 4.5
Step-by-step explanation:
See attached worksheet.
Answer:
As per the statement:
Adult red wolves vary in length from 137.16 cm to 168.64 cm.
To find the difference in length between the longest and shortest of these wolves.
Longest length of wolves = 168.64 cm
Shortest length of wolves= 137.16 cm
Then;
=
Substitute the given values we have;
= 168.64 - 137.16 = 31.48 cm
therefore, the difference in length between the longest and shortest of these wolves is 31.48 cm