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omeli [17]
3 years ago
15

Robe is twice joshuas age .nick is 5 years older than joshua

Mathematics
1 answer:
Taya2010 [7]3 years ago
3 0
Oldest to youngest

Robe, Nick, Joshua
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Write an explicit formula for an, the nth term of the sequence 4, -24, 144, ....
nadezda [96]

Answer:

Tn = 4(-6)^n-1

Step-by-step explanation:

Write an explicit formula for an, the nth term of the sequence 4, -24, 144, ....

The sequence is a geometric sequence

Tn = ar^n-1

a is the first term

a = 4

r = -24/4 =144/-24

r = -6

Substitute

Tn = 4(-6)^n-1

3 0
2 years ago
Sam wants to build a wooden deck on his patio, which is in the shape of a parallelogram. The area of the patio is 280 ft 2. Find
Radda [10]

Answer: The base is 18.3ft

Sam wants to build a wooden deck on his patio, which is in the shape of a parallelogram. The area of the patio is 280 ft2. Find the base. Round your answer to the nearest foot. (height=5x)(base=6x)

Step-by-step explanation:

Given;

Area = 280ft^2

height = 5x

Base = 6x

The area of the parallelogram A can be written as;

Area = base × height

A = b×h

Substituting the values of Area, base and height.

280 = 5x × 6x

280 = 30x^2

x^2 = 280/30

x = √(280/30)

Since the base = 6x ;

Substituting the value of x.

Base = 6x = 6(√(280/30))

Base = 18.3ft

The base is 18.3ft

4 0
3 years ago
What is the scale factor of the dilation?
VLD [36.1K]
The rule for dilation (scale factor k) about the origin is given by:
(x,y)->(kx,ky)

The scale factor k can be obtained from any one of the ratios:
scale\, factor\, =\, k\, = \frac{OD'}{OD}=\frac{OE'}{OE}=\frac{OF'}{OF}=\frac{OG'}{OG}=\frac{1}{2}
6 0
2 years ago
Read 2 more answers
<img src="https://tex.z-dn.net/?f=%20%5Crm%20%5Cint_%7B0%7D%5E2%20%5Cleft%28%20%5Csqrt%5B3%5D%7B%20%7Bx%7D%5E%7B2%7D%20%20%2B%20
Verizon [17]

If f(x) has an inverse on [a, b], then integrating by parts (take u = f(x) and dv = dx), we can show

\displaystyle \int_a^b f(x) \, dx = b f(b) - a f(a) - \int_{f(a)}^{f(b)} f^{-1}(x) \, dx

Let f(x) = \sqrt{1 + x^3}. Compute the inverse:

f\left(f^{-1}(x)\right) = \sqrt{1 + f^{-1}(x)^3} = x \implies f^{-1}(x) = \sqrt[3]{x^2-1}

and we immediately notice that f^{-1}(x+1)=\sqrt[3]{x^2+2x}.

So, we can write the given integral as

\displaystyle \int_0^2 f^{-1}(x+1) + f(x) \, dx

Splitting up terms and replacing x \to x-1 in the first integral, we get

\displaystyle \int_1^3 f^{-1}(x) \, dx + \int_0^2 f(x) \, dx = 2 f(2) - 0 f(0) = 2\times3+0\times1=\boxed{6}

7 0
1 year ago
Y=1/3x + 2 what is the domain?
Trava [24]

Answer:

To find the domains you must graph this equation and find the x-coordinates of the points plotted. That's the domain.

Remember, if two points have the same x-coordinate then do not repeat the number when stating the domain. Domain also always must be written in the least to greatest order. Domains must be written with {} enclosing them.

So if the x-coordinates were 4,5,6,4,7,5

You would write the domain as {4,5,6,7}

5 0
2 years ago
Read 2 more answers
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