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Daniel [21]
4 years ago
8

The first row of a conference hall has 8 chairs and 2 additional chairs in each subsequent row. How many chairs are in the 9th r

ow? How many chairs in total are in the first 9 rows?
Mathematics
1 answer:
Anna35 [415]4 years ago
4 0

Ans:

24 chairs in 9th row and 144 chairs in ist 9th rows

Step-by-step explanation:

ist row= 8

2nd = 10

3rd =  12

.

.

.

9th row = 24

and if we add all chairs = 8+10+12+14+16+18+20+22+24= 144

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The two triangles formed will be ADB and BCD

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3 years ago
Translate the sentence into an equation using n to represent the unknown number. Then solve the equation for n.
Ulleksa [173]
Let the unknown number be "n",

This number is sutracted from 46. So, 46 less n.
That is (46 - n).
The result to this is -21.
∴The equation would be;

46 - n = -21.
Now solve for n.
46-n=-21
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∴n=67
7 0
3 years ago
Read 2 more answers
Which of the following expressions is equal to <br> -3x^2 - 27 ?
Alborosie

Answer: D. -3x+9i)(x+3i) i hope this helped :)

3 0
3 years ago
Use the "rule of 72" to estimate the doubling time (in years) for the interest rate, and then calculate it exactly. (Round your
Law Incorporation [45]

Answer:

According to the rule of 72, the doubling time for this interest rate is 8 years.

The exact doubling time of this amount is 8.04 years.

Step-by-step explanation:

Sometimes, the compound interest formula is quite complex to be solved, so the result can be estimated by the rule of 72.

By the rule of 72, we have that the doubling time D is given by:

D = \frac{72}{Interest Rate}

The interest rate is in %.

In our exercise, the interest rate is 9%. So, by the rule of 72:

D = \frac{72}{9} = 8.

According to the rule of 72, the doubling time for this interest rate is 8 years.

Exact answer:

The exact answer is going to be found using the compound interest formula.

A = P(1 + \frac{r}{n})^{nt}

In which A is the amount of money, P is the principal(the initial sum of money), r is the interest rate(as a decimal value), n is the number of times that interest is compounded per unit t and t is the time the money is invested or borrowed for.

So, for this exercise, we have:

We want to find the doubling time, that is, the time in which the amount is double the initial amount, double the principal.

is double the initial amount, double the principal.

A = 2P

r = 0.09

The interest is compounded anually, so n = 1

A = P(1 + \frac{r}{n})^{nt}

2P = P(1 + \frac{0.09}{1})^{t}

2 = (1.09)^{t}

Now, we apply the following log propriety:

\log_{a} a^{n} = n

So:

\log_{1.09}(1.09)^{t} = \log_{1.09} 2

t = 8.04

The exact doubling time of this amount is 8.04 years.

4 0
4 years ago
I need the help as possible please somebody help me I need help I swear please somebody help me help me help me please someone h
muminat

Here is your answer

A. (4,-7)

REASON:

In quadrant IV abscissa is +ve and ordinate is -ve. Since absolute value is 11

Here |4|+|-7|= 4+7= 11

HOPE IT IS USEFUL

3 0
4 years ago
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