A cliff forms an angle of x∘ with a lake. If you stand on the edge of the cliff and throw a rock at a distance of 48 ft to the w
ater, the rock will strike the water about 5 ft from the base of the cliff. What is measure of the angle that the cliff forms with the lake? Round your answer to the nearest whole degree.
1 answer:
Answer:
∅=6°
Step-by-step explanation:
we have that the distance from the edge of the cliff to the lake is 48 feet, and when the stone is thrown into the lake it collides with the water 5 feet from the base of the cliff so you must find the distance that the stone travels from the edge of the sewer up to 5 feet beyond its base (hypotenuse) and then the angle that forms it (slope)
Hypotenuse (c)
:
Slope ∅
Sin∅ = 5ft/48.25ft = 0.1036
∅=arcsin(0.1036) ≅ 5.9°, but how should we round to the nearest integer
, then:
∅=6°
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Answer:
We assume that the orange is dropped at t = 0s.
Once the orange is on the air, the only force acting on it is the gravitational force, then the acceleration of the orange is the gravitational acceleration.
A(t) = -32.17 ft/s^2
Where the negative sign is because this acceleration points downwards.
For the velocity equation, we need to integrate over time, we will get:
V(t) = (-32.17 ft/s^2)*t + V0
Where V0 is the initial vertical velocity of the orange, because the orange is accidentally dropped, this initial velocity is equal to zero.
V(t) = (-32.17 ft/s^2)*t
For the position equation we need to integrate again, this time we get:
P(t) = (1/2)*(-32.17 ft/s^2)*t^2 + P0
Where P0 is the initial height of the orange, we know that it is 40ft, then the position equation is:
P(t) = (1/2)*(-32.17 ft/s^2)*t^2 + 40 ft
Now that we know the equation, we can graph it. (you can see the graph below)
Now we also want to find at what time does the orange hit the water.
This happens when:
P(t) = 0 ft = (1/2)*(-32.17 ft/s^2)*t^2 + 40 ft
We just need to solve that equation for t.
0 ft = (1/2)*(-32.17 ft/s^2)*t^2 + 40 ft
(1/2)*(32.17 ft/s^2)*t^2 = 40 ft
t^2 = (40ft)/( (1/2)*(32.17 ft/s^2))
t = √( (40ft)/( (1/2)*(32.17 ft/s^2)) ) = 1.58 s
The orange hits the water 1.58 seconds after it is dropped.
Answer:
See picture attached
Step-by-step explanation:
See picture attached
