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3 years ago

I need the answer ASAP please

Mathematics

1 answer:

Alisiya [41]3 years ago

8 0

Answer:

Step-by-step explanation:

$-c\leq21\qquad\text{change the signs (flip the inequality sign)}\\\\c\geq-21$

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Given: △FKL, FK=a

LuckyWell [14K]

Answer:

$FL= \frac{a (\sqrt{3} + 1)}{\sqrt{2} }$

Step-by-step explanation:

As given in figure 1 below:

FK = a, m∠F = 45° and m∠L = 30°

Construction: Draw an altitude KE from point K on FL.

Now, In ΔFEK,

FE = EK (Sides opposite to equal angles of a triangle)

Let FE = EK = x

Now, using pythagoras In ΔFEK,

$(FK)^{2} = (FE)^{2} + (KE)^{2}$

$(a)^{2} = (x)^{2} + (x)^{2}$

$(a)^{2} = 2x^{2}$

$x = \sqrt \frac{a^{2} }{2} = \frac{a}{\sqrt{2} }$

∴ FE = EK = $\frac{a}{\sqrt{2} }$

Now in ΔEKL, EK = $\frac{a}{\sqrt{2} }$

Using trigonometry ratio,

TanФ = Altitude\ Base

$Tan \theta = \frac{KE}{EL}$

Tan 30° = $\frac{a/\sqrt{2} }{EL}$

$\frac{1}{\sqrt{3} } = \frac{a}{\sqrt{2} EL}$

$EL = \frac{\sqrt{3}a}{\sqrt{2} }$

Now FL = FE + EL

FE = $\frac{a}{\sqrt{2} }$ and $EL = \frac{\sqrt{3}a}{\sqrt{2} }$

∴ $FL = \frac{a}{\sqrt{2} } + \frac{\sqrt{3}a }{\sqrt{2} } = \frac{a (\sqrt{3} + 1)}{\sqrt{2} }$

4 0

4 years ago

Twice the quotient of 50 and the sum of a number y and 8

djverab [1.8K]

1st the sum of y and 8 is
y+8
the quotient of 50 and (y+8) is simply dividing 50 by (y+8)
50 / (y+8)
Twice <span>the </span>quotient mean multiply <span>50 / (y+8) by 2, so t</span>he answer is:
2 * 50 / (y+8)

4 0

3 years ago

Type the correct answer in the box.

Igoryamba

The area of the figure is 80 units

3 0

3 years ago

PLEASE ANSWER ALL THESE QUESTION FOR 75 POINTS!!

Alika [10]

1. 9
2. 24
3. 10
4. 4
yw!

8 0

3 years ago

Read 2 more answers

(-2+1)+5(12 divided by 3)-9

Kay [80]

Answer:

Step-by-step explanation:

(-2+1)+5(12\3)-9

(-1)+5(4)-9

-1+20-9

4 0

3 years ago