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dezoksy [38]
3 years ago
8

If you deposit $5,000 in an account that earns 2% interest, compounded continuously, how much money will be in the account after

seven years?
$5,751.37

$5,743.43

$5.101.01

None of the above
Mathematics
1 answer:
Ksivusya [100]3 years ago
5 0

Answer:

$5751.37

Step-by-step explanation:

The key phrase here is "compounded continuously".  This phrase tells you that you must use the following equation:


A=Pe^{rt}

Where A is the final amount, P is the principal amount, e is the exponential constant, r is the rate in decimals and t is time.  By plugging in our known values given we obtain:


A=5000e^{0.02 \times 7}=5751.37

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2 years ago
700+a=3944-b=c-80=3000​
velikii [3]

Answer:

A = 3244

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Step-by-step explanation:

 700 + a = 3944

 -700          -700

a = 3244

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c - 80 = 3000

  +80       +80

c = 3080

3944 - b = c ---> 3944 - b = 3080

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3 years ago
Select all the expressions that are equivalent to (2)^n+³
eimsori [14]

Answer:

The expressions which equivalent to  (2)^{n+3} are:

4(2)^{n+1}  ⇒ B

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Step-by-step explanation:

Let us revise some rules of exponent

  • a^{m} × a^{m}  = a^{m+n}
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Now let us find the equivalent expressions of  (2)^{n+3}

A.

∵ 4 = 2 × 2

∴ 4 =  2^{2}

∴  (4)^{n+2} =  (2^{2})^{n+2}

- By using the second rule above multiply 2 and (n + 2)

∵ 2(n + 2) = 2n + 4

∴  (4)^{n+2} =  (2)^{2n+4}  

B.

∵ 4 = 2 × 2

∴ 4 =  2²

∴  4(2)^{n+1} = 2² ×  (2)^{n+1}

- By using the first rule rule add the exponents of 2

∵ 2 + n + 1 = n + 3

∴   4(2)^{n+1} =  (2)^{n+3}

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∵ 8 = 2 × 2 × 2

∴ 8 =  2³

∴  8(2)^{n} = 2³ ×  (2)^{n}

- By using the first rule rule add the exponents of 2

∵ 3 + n = n + 3

∴  8(2)^{n} =  (2)^{n+3}

D.

∵ 16 = 2 × 2 × 2 × 2

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∴  16(2)^{n} = 2^{4}  ×  (2)^{n}

- By using the first rule rule add the exponents of 2

∵ 4 + n = n + 4

∴  16(2)^{n} =  (2)^{n+4}

E.

(2)^{2n+3} is in its simplest form

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4(2)^{n+1}  ⇒ B

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Answer:

Step-by-step explanation:

We can use the process of elimination as

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—————————

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