Answer:
Code is given below and output is attached as an image.
Explanation:
#include <iostream>
#include <fstream>
using namespace std;
bool isPalindrome(int n)
{
// Find reverse of n
int rev = 0;
for (int i = n; i > 0; i /= 10)
rev = rev * 10 + i % 10;
// If n and rev are same,then n is a palindrome
return (n == rev);
}
int main()
{
int min = 1; // Lower Bound
int max = 200; // Upper Bound
ofstream myfile;
myfile.open("palindrome.txt");
for (int i = min + 1; i < max; i++)
if (isPalindrome(i))
myfile << i << endl;
myfile.close();
return 0;
}
Answer:
C. &&
Explanation:
Of the options provided:
A) ++ : increment operator. For example : ++1 = 2
B) || : Logical OR operator. A || B is true if any one of A or B is true.
C) && : Logical AND operator. A && B is true if both A and B are true.
A B A && B
False False False
False True False
True False False
True True True
D) @ : Ampersand character (commonly used in email addresses) e.g, [email protected]
D size
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Hope,this helped
Answer:
A
Explanation:
In my opinion, it is best he works the extra $1300 which wouldn't require him to abandon his college plans, wait an extra year or get himself into the trouble of loans.
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