Answer:
The horizontal distance from the plane to the person on the runway is 20408.16 ft.
Step-by-step explanation:
Consider the figure below,
Where AB represent altitude of the plane is 4000 ft above the ground , C represents the runner. The angle of elevation from the runway to the plane is 11.1°
BC is the horizontal distance from the plane to the person on the runway.
We have to find distance BC,
Using trigonometric ratio,
Here, 
,Perpendicular AB = 4000
Solving for BC, we get,
(approx)
(approx)
Thus, the horizontal distance from the plane to the person on the runway is 20408.16 ft
Answer:
17 is the answer
Step-by-step explanation:
The values which completes the table regarding summer camp is option b which is a=15,b=7, c=5, d=10, e=12.
Given that there are 32 campers, 22 of them can swim, 20 play softball and 5 do not play softball or swim.
We have to find the values of a,b,c,d,e so that we can complete the table.
Table is a combination of rows and columns. In our case the third row and third column shows the total.
from the table we can write that 22+d=32-----------1
so d=32-22
=10
d=10
c+5=d-----------2
c=10-5=5
c=5
a+c=20------------------3
a+5=20
a=20-5
a=15
a+b=22--------------3
15+b=22
b=7
20+e=32----------4
e=32-22
e=10.
Hence the values which completes the table is a=15,b=7, c=5, d=10, e=12.
Learn more about table at brainly.com/question/12151322
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Question is incomplete as it should include figure showing table of values.
<h2><u>Answer :</u></h2>
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<h2><u>Calculation</u><u> </u><u>:</u></h2>
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3/5 of the total responses expected = 87...
3/5x = 87
x = 87 / (3/5)
x = 87 * 5/3
x = 435/3
x = 145 <=== what was expected
