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sveticcg [70]
3 years ago
5

To determine the wind speed in a certain location, 40 samples are taken in a limited period of time. The average value of the me

asurements is 30 miles per hour, and the standard deviation of the sample is 2 miles per hour. Determine a 95% confidence interval for the mean value of the wind speed.
Mathematics
1 answer:
tensa zangetsu [6.8K]3 years ago
5 0

Answer: 95% confidence interval is (29.38, 30.62).

Step-by-step explanation:

Since we have given that

n = Sample size = 40

Average value = 30 miles per hour

Standard deviation = 2 miles per hour

We need to find the interval for 95% confidence interval.

So, z = 1.96

So, the intervals would be

\bar{x}\pm z\dfrac{\sigma}{\sqrt{n}}\\\\=30\pm 1.96\times \dfrac{2}{\sqrt{40}}\\\\=30\pm 0.62\\\\=(30-0.62,30+0.62)\\\\=(29.38,30.62)

Hence, 95% confidence interval is (29.38, 30.62).

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<h3>What is the range?</h3>

The range is the difference between the maximum and minimum.

Given to us

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The discrepancy in diameter is more than 0.002 mm.

As it is given to us that the standard diameter of the golf ball is 42.67 mm while the discrepancy in diameter is more than 0.002 mm.

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Hence, the maximum and minimum acceptable diameter of the golf ball in the factory will be 42.672 mm to 42.668 mm.

Learn more about Range:

brainly.com/question/3507706

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