Answer:
(–5, –7)
Step-by-step explanation:
From the question given above, the following data were obtained:
Slope = 9/5
Coordinate 1 = (–10, –16)
x₁ = –10
y₁ = –16
Coordinate 2 = (x₂, y₂)
Next, we shall determine the change in x and y coordinate. This can be obtained as follow:
Slope = change in y–coordinate / change in x–coordinate
Slope = Δy / Δx
Slope = 9/5
9/5 = Δy / Δx
Thus,
Δy = 9
Δx = 5
Next, we shall determine the second coordinates as follow:
Δy = y₂ – y₁
Δx = x₂ – x₁
For x–coordinate:
x₁ = –10
Δx = 5
Δx = x₂ – x₁
5 = x₂ – (–10)
5 = x₂ + 10
Collect like terms
x₂ = 5 – 10
x₂ = – 5
For y–coordinate:
y₁ = –16
Δy = 9
Δy = y₂ – y₁
9 = y₂ – (–16)
9 = y₂ + 16
Collect like terms
y₂ = 9 – 16
y₂ = – 7
Coordinate 2 = (x₂, y₂)
Coordinate 2 = (–5, –7)
1. Part 14/25
Total .56
Percent56%
2. 16/20
Total. .8
Percent 80%
3. 11/20 55%
4. 40
5. 300%
6. 140
To solve this problem, we must recall that the formula
for velocity assuming linear motion:
v = d / t
Where,
v = velocity
d = distance
t = time
For condition 1: bus travelling on a level road
v1 = d1 / t1
<span>(v2 + 20) = (449 – d2) / 4 --->1</span>
For condition 2: bus travelling on a winding road
v2 = d2 / t2
<span>v2 = d2 / 5 --->2</span>
Combining equations 1 and 2:
(d2 / 5) + 20 = (449 – d2) / 4
0.8 d2 + 80 = 449 – d2
1.8 d2 = 369
d2 = 205 miles
Using equation 2, find for v2:
v2 = 205 / 5
v2 = 41 mph
Since v1 = v2 + 20
v1 = 41 + 20
v1 = 61 mph
Therefore
<span>the
average speed on the level road is 61 mph.</span>
2=6
3=9
9=27
You just times the number in box X three times
I don't know the rest of the question but
$4.50 is looking good!!
