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icang [17]
3 years ago
12

2oz+2.5lbs+1/4lbs= How do I find the answer

Mathematics
2 answers:
Anton [14]3 years ago
7 0
Well you have to convert the pounds to ounces
1 pound = 16 ounces
2oz+40oz+4oz
46oz
myrzilka [38]3 years ago
5 0
The answer is 46oz


Hope this helps
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find the parametric equations for the line of intersection of the two planes z = x + y and 5x - y + 2z = 2. Use your equations t
Kaylis [27]

Answer:

You didn't give the points in which you want the parametric equations be filled, but I have obtained the parametric equations, and they are:

x = (1/3 + t)

y = (-1/3 - 7t)

z = -6t

Step-by-step explanation:

If two planes intersect each other, the intersection will always be a line.

The vector equation for the line of intersection is given by

r = r_0 + tv

where r_0 is a point on the line and v is the vector result of the cross product of the normal vectors of the two planes.

The parametric equations for the line of intersection are given by

x = ax, y = by, and z = cz

where a, b and c are the coefficients from the vector equation

r = ai + bj + ck

To find the parametric equations for the line of intersection of the planes.

x + y - z = 0

5x - y + 2z = 2

We need to find the vector equation of the line of intersection. In order to get it, we’ll need to first find v, the cross product of the normal vectors of the given planes.

The normal vectors for the planes are:

For the plane x + y - z = 0, the normal vector is a⟨1, 1, -1⟩

For the plane 5x - y + 2z = 2, the normal vector is b⟨5, -1, 2⟩

The cross product of the normal vectors is

v = a × b =

|i j k|

|1 1 -1|

|5 -1 2|

= i(2 - 1) - j(2 + 5) + k(-1 - 5)

= i - 7j - 6k

v = ⟨1, -7, -6⟩

We also need a point on the line of intersection. To get it, we’ll use the equations of the given planes as a system of linear equations. If we set z = 0 in both equations, we get

x + y = 0

5x - y = 2

Adding these equations

5x + x + y - y = 2 + 0

6x = 2

x = 1/3

Substituting x = 1/3 back into

x + y = 0

y = -1/3

Putting these values together, the point on the line of intersection is

(1/3, -1/3, 0)

r_0= (1/3) i - (1/3) j + 0 k

r_0​​ = ⟨1/3, -1/3, 0⟩

Now we’ll plug v and r_0​​ into the vector equation.

r = r_0​​ + tv

r = (1/3)i - (1/3)j + 0k + t(i - 7j - 6k)

= (1/3 + t) i - (1/3 + 7t) j - 6t k

With the vector equation for the line of intersection in hand, we can find the parametric equations for the same line. Matching up r = ai + bj + ck with our vector equation,

r = (1/3 + t) i + (-1/3 - 7t) j + (-6t) k

a = (1/3 + t)

b = (-1/3 - 7t)

c = -6t

Therefore, the parametric equations for the line of intersection are

x = (1/3 + t)

y = (-1/3 - 7t)

z = -6t

3 0
3 years ago
Please find answer. ​
Anuta_ua [19.1K]

Answer:

Again, the answer is (1,-2)

Step-by-step explanation:

Substitute the values

8 0
3 years ago
What is the answer for baby eleaphants
Tatiana [17]

Answer:

3?

Step-by-step explanation:

im not sure tho

5 0
3 years ago
Use the reverse tabular method to solve division problem: (x^3+2x^2+2x+1)/(x+1)
belka [17]

Answer:

x^2+x+1

Step-by-step explanation:

Your welcomeeee

7 0
3 years ago
What is the measure of 4?
zlopas [31]

Answer:

∠ 4 = 80°

Step-by-step explanation:

∠ 5 and 100° are vertical angles and are congruent , so

∠ 5 = 100°

∠ 4 and ∠ 5 are same- side interior angles and sum to 180° , that is

∠ 4 + ∠ 5 = 180°

∠ 4 + 100° = 180° ( subtract 100° from both sides )

∠ 4 = 80°

8 0
2 years ago
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