Answer:
5 units
Step-by-step explanation:
Calculate the distance d using the distance formula
d = 
with (x₁, y₁ ) = (2, 1) and (x₂, y₂ ) = (6, 4)
d = 
= 
= 
= 
= 5
Look at deonomators
assuming that the deonomenators are 5x+15y and 2x+6y
find their LCM
factor
5x+15y=5(x+3y)
2x+6y=2(x+3y)
LCM=10(x+3y)=10x+30y
multiply 2/(5x+15y) by 2/2=4/(10x+30y)
multiply 1/(2x+6y) by 5/5=5/(10x+30y)
if we add them
9/(10x+30y)
I’m pretty sure it’s 2 but i’m not 100 percent on that