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Lera25 [3.4K]
3 years ago
5

Graph the line -3x+y=-6 I need two pairs of points

Mathematics
1 answer:
snow_lady [41]3 years ago
6 0

Answer:

point 1 (0,-6)

point 2(2,0)

Step-by-step explanation:

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Please helppp answer correctly !!!!!!!!!!!!!! Will mark Brianliest !!!!!!!!!!!!!!!
horrorfan [7]

Answer:

21

Step-by-step explanation:

Remember that the centroid splits the 3 medians of a triangle into a ratio of 1:2

Since TS < TN, TS = 42/2 = 21

7 0
2 years ago
This is stem and leaf diagrams and there are a few coming up try answer them all for more points each time!!
AURORKA [14]

Answer:

78%

Step-by-step explanation:

Given the stem and leaf plot above, to find the median percentage for boys in the German test, first, write out the data set given in the stem and leaf diagram as follows:

40, 46, 46, 47, 69, 70, [78, 78,] 79, 82, 87, 90, 90, 95

The median value is the middle value in the data set. In this case, we have an even number of data set which are 14 in number.

The median for this data set would be the average of the 7th and 8th value = (78+78) ÷ 2 = 156/2 = 78

Median for boys = 78%

7 0
3 years ago
Is 3/7 and 7/3 the same on the number length in the fraction line?
Goshia [24]
No, 3/7 and 7/3 are not the same in the fraction line. It's because 3/7 is less than 1, while 7/3 is as much as 2 1/3.

I hope it will help you mate :)
3 0
3 years ago
Suppose that Ayumi rolls a pair of fair six-sided dice. Let A be the event that the first die lands on 2 and B be the event that
Tanya [424]

Answer:

\frac{1}{6} ,\frac{1}{6} ,\frac{1}{36}\,,\,independent

Step-by-step explanation:

Given: Let A be the event that the first die lands on 2 and B be the event that the second die lands on 2.

To find:

P(A), the probability that the first die lands on 2

P(B), the probability that the second die lands on 2

P(A and B): the probability that the first die lands on 2 and the second die lands on 2

Solution:

Probability refers to chances of occurrence of some event.

Probability = number of favourable outcomes/total number of outcomes

Sample space = \left \{ 1,2,3,4,5,6 \right \}

Total number of outcomes = 6

For P(A):

Number of favourable outcomes = 1

So,

P(A)=\frac{1}{6}

For P(B):

Number of favourable outcomes = 1

So,

P(B)=\frac{1}{6}

P(A and B) = P(A)P(B)=\left ( \frac{1}{6} \right )\left ( \frac{1}{6} \right )=\frac{1}{36}

Yes, A and B are independent events as happening of each of the event does not depend on the other.

5 0
3 years ago
Eric has seventeen candy bars, he gives Debra five. How many candy bars does Eric have now?
sergejj [24]
17-5=12
So Eric has 12 candy bars
8 0
3 years ago
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