Answer:
Mean: 29.5; Median: 26; Modes: 25, 26
Step-by-step explanation:
Add 10+12+25+25+26+26+30+31+33+34+47+55 = 354
Then divide it by 12 354/12 = 29.5
Mode are numbers that appear most often which in this case are 2 numbers, 25 and 26.
IN Δ MLN:
∠M = 18.3 , ∠L = 98.6 AND ∠N = 180 - (∠M + ∠L) = 180 - (18.3 + 98.6 ) = 63.1
IN Δ FGH:
∠F = 98.6 , ∠G = 61.1 AND ∠H = 180 - (∠F + ∠G ) = 180 - (98.6 + 61.1 ) = 20.3
∴ ONLY ∠N = ∠F = 98.6
There is no other <span>congruent </span>angles
So, The correct statement is :
Inaccurate. The triangles are not similar because angle M is not congruent to angle H, and angle N is not congruent to angle G.
Answer:
V = 6079.04 ft³
Step-by-step explanation:
The volume (V) of a cylinder is calculated as
V = πr²h ( r is the radius and h the height )
Here diameter = 22 , then r = 22 ÷ 2 = 11 and h = 16 , then
V = 3.14 × 11² × 16
= 3.14 × 121 × 16
≈ 6079.04 ft³ ( to the nearest hundredth )
Answer:
m=2 and n=3
Step-by-step explanation:
<u>Step</u> :-
Given ![[ 2 x^{n}y^{2} ]^m = 4 x^6 y^4](https://tex.z-dn.net/?f=%5B%202%20x%5E%7Bn%7Dy%5E%7B2%7D%20%5D%5Em%20%3D%204%20x%5E6%20y%5E4)
using algebraic formula 
now

now equating 'x' powers, we get

....(1)
now

Equating 'y' powers ,we get
2 m=4
m=2
substitute m= 2 in equation (1)
we get
2 n=6
n=3
verification:-
substitute m=2 and n=3 , we get
![[ 2 x^{n}y^{2} ]^m = 4 x^6 y^4](https://tex.z-dn.net/?f=%5B%202%20x%5E%7Bn%7Dy%5E%7B2%7D%20%5D%5Em%20%3D%204%20x%5E6%20y%5E4)


both are equating so m= 2 and n=3