Answer:
<em>The perimeter of given figure = 56.56 ft</em>
Step-by-step explanation:
<u>Step(i):-</u>
From diagram
The length of the rectangle = 10 ft
The width of the rectangle = 8 ft
Perimeter of the rectangle
= 2 ( l+w)
= 2 ( 10 + 8)
= 2 × 18
= 36
<u><em>Step(ii):-</em></u>
The semi circle is included in the given diagram
<em>Now we will find the perimeter of semicircle</em>
<em>We know that </em>
<em> perimeter of the circle </em>
<em> p = 2πr + d</em>
<em> perimeter of the semicircle</em>
<em> </em>
<em></em>
<em> P = πr + 2 r (∵ d = 2 r)</em>
<u><em>Step(iii):-</em></u>
<em> From diagram the diameter of semicircle is equal to the width of the rectangle </em>
<em> d = 8</em>
<em> d = 2 r = 8</em>
<em> The radius of the circle 'r' = 4 </em>
<em> perimeter of the semicircle</em>
<em> P = πr + 2 r </em>
<em> P = 3.14 ( 4) + 8</em>
<em> P= 20.56</em>
<u><em>Conclusion:-</em></u>
<em>The perimeter of given figure</em>
<em> = perimeter of rectangle + perimeter of semicircle</em>
= 36 + 20.56
=56.56 ft
No, because it <em>is not a straight line when graphed.</em>
<span>The y-intercept of is .
Of course, it is 3 less than , the y-intercept of .
Subtracting 3 does not change either the regions where the graph is increasing and decreasing, or the end behavior. It just translates the graph 3 units down.
It does not matter is the function is odd or even.
is the mirror image of stretched along the y-direction.
The y-intercept, the value of for , is</span><span>which is times the y-intercept of .</span><span>Because of the negative factor/mirror-like graph, the intervals where increases are the intervals where decreases, and vice versa.
The end behavior is similarly reversed.
If then .
If then .
If then .
The same goes for the other end, as tends to .
All of the above applies equally to any function, polynomial or not, odd, even, or neither odd not even.
Of course, if polynomial functions are understood to have a non-zero degree, never happens for a polynomial function.</span><span> </span>
Answer:
An airline estimates that 94% of people booked on their flights actually show up. If the airline books 77 people on the flight for which the maximum number is 75, what is the probability that the number of people who show up will exceed the capacity of the plane?
-------------------------
Binomial Problem with n = 77 and p = 0.94
---
P(76 <= x <= 77) = 1-P(0 <=x <= 75) = 1 - binomcdf(77,0.94,75) = 0.0504
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Cheers,
Stan H.
Answer: =2/5 x
Step-by-step explanation: