Find the value of x
2 answers:
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Let's factor all four of these before we multiply.
x² - 25
We want two numbers that add to -25 and multiply to 0.
= (x+5)(x-5)
x² - 2x
Both terms are divisible by x.
= x(x-2)
x - 2
unfactorable
x² + 5x
Both terms are divisible by x.
= x(x+5)
Now we have this:
Let's go ahead and multiply across.
Cancel out the (x+5) and (x-2) from the top and the bottom.
Answer:
x = sqroot(122)
Step-by-step explanation:
First find the line that goes thru the middle of the shape. It is the hypotenuse of the bottom/left triangle. Use the pythagorean thm.
9^2 + 5^2 = h^2
81 + 25 = h^2
sqroot106 = h
Now sqroot106 is a leg in the right triangle that is on the top/right in the image.
Use pythagorean thm again.
4^2 + (sqroot106)^2
= x^2
16 + 106 = x^2
122 = x^2
sqroot122 = x
