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3 years ago

5

Please help me guys

1 answer:

steposvetlana [31]3 years ago

6 0

Answer:

1079.94

Step-by-step explanation:

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3/13

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A circle has a radius of 11 inches and a central angle AOB that measures 45°. What is the area of sector AOB? Use 3.14 for pi an

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X=square root of 880-8x

Sunny_sXe [5.5K]

$x=\sqrt{880-8x}\\
D:880-8x\geq0 \wedge x\geq0\\
D:8x\leq880 \wedge x\geq0\\
D:x\leq 110 \wedge x\geq0\\
D:x\in\langle0,110\rangle\\
x^2=880-8x\\
x^2+8x-880=0\\
x^2+8x+16-896=0\\
(x+4)^2=896\\
x+4=8\sqrt{14} \vee x+4=-8\sqrt{14}\\
x=-4+8\sqrt{14} \vee x=-4-8\sqrt{14}\\
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3 years ago

Please I need answers Factorize x²-6x+9

miskamm [114]

Answer:

The factors of the given equation are:

$x^2-6x+9=(x-3)(x-3)=(x-3)^2$

Step-by-step explanation:

We have :

$x^2-6x+9$

Using middle term splitting theorem to factorize the expression :

$x^2-3x-3x+9$

$x(x-3)+(-3)(x-3)$

$(x-3)(x-3)$

$x^2-6x+9=(x-3)(x-3)=(x-3)^2$

The factors of the given equation are:

$x^2-6x+9=(x-3)(x-3)=(x-3)^2$

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3 years ago

E=mc squared m=3 c=6

dsp73

Answer:

E = 108

Step-by-step explanation:

E = 3 * $6^{2}$

= 108

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